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stepan [7]
3 years ago
11

Trey needs to find the zero of the equation 9x + 2y = 18. Which describes the steps he should take?

Mathematics
1 answer:
Fudgin [204]3 years ago
3 0

Answer:

a. Substitute 0 for x and solve for y

b. Substitute 0 for y and solve for x

Step-by-step explanation:

Getting the zeros of the given equation is similar to finding the x-intercept and y-intercept of the equation

The x intercept occurs where y = 0

Substituting y = 0 into the expression and getting x we have;

9x + 2y = 18

9x +2(0)= 18

9x = 18

x = 18/9

x=2

Hence the x intercept is 2

Similarly, to get the y intercept, we will substitute x = 0 and get the value of x a shown:

When x =0.

9(0)+2y = 18

0+2y = 18

2y= 18

y = 18/2

y = 9

Hence the zeros of the equations occurs at (2, 9)

The correct options are

-Substitute 0 for x and solve for y

-Substitute 0 for y and solve for x

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Circle A is shown. Secant W Y intersects tangent Z Y at point Y outside of the circle. Secant W Y intersects circle A at point X
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Circle A is missing, so i have attached it.

Answer:

∠XYZ = 35°

Step-by-step explanation:

We want to find the angle ∠XYZ in the image attached.

To solve that, we will use the formula in the theorem for angle formed by secants or tangents. Thus;

∠XYZ = ½(arc WZ - arc XZ)

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Thus;

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What is the value of i^n in if the remainder of n/4 is 2?
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The value of {i^n} is \boxed{ - 1} if the remainder of \dfrac{n}{4} is 2.

Further Explanation:

Given:

The remainder of \dfrac{n}{4} is 2.

Explanation:

The sum of imaginary numbers and real numbers is known as the complex number.

The complex number can be expressed as follows,

\boxed{z = a + ib}

Here, a is the real part of the complex number and \text{ib} is the imaginary part of the complex number.

\sqrt{ - 1} can be denoted by i.

The value of {i^2} is -1.

{i^2} =  - 1

The value {i^3} can be obtained as follows,

\begin{aligned}{i^3}&= {i^2} \times i\\&= - 1 \times i \\&= - i\\\end{aligned}

The value {i^4} can be obtained as follows,

\begin{aligned}{i^4} &= {i^2} \times {i^2}\\&= - 1 \times - 1 \\&= 1\\\end{aligned}

The value of {i^n} is \boxed{ - 1} if the remainder of \dfrac{n}{4} is 2.

Learn more:

  1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
  2. Learn more about equation of circle brainly.com/question/1506955.
  3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: Middle School

Subject: Mathematics

Chapter: Complex numbers

Keywords: value, i^ n, remainder, n/4, 2 quotient, divisor, complex number, imaginary number, real number, exponents, dividend, powers, -1, imaginary roots.

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