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Lilit [14]
4 years ago
9

I need some help with this question

Mathematics
1 answer:
soldier1979 [14.2K]4 years ago
6 0
(55w+145) is the answer
You might be interested in
This might be kinda stupid but am kinda confused
Alex

Answer:

B,

3/4=9/12

2/3=8/12

9/12>8/12

B

4 0
3 years ago
Pleas help and only answer if you know it and put the number by which one you answer
MA_775_DIABLO [31]

There is a thing that you can do on there to find the answers all u do is crtl u then scroll all the way down

5 0
3 years ago
2x² - x-6=0 resuelve
Vika [28.1K]

Answer:

x = -3/2          x=2

Step-by-step explanation:

2x² - x-6=0

Factor

(2x     ) (x      ) =0

6 = 2*3

2*-2 +3 = -1

(2x  +3   ) (x  -2    ) =0

2x+3 =0      x-2 =0

2x = -3            x=2

x = -3/2          x=2

6 0
3 years ago
Melanie buys a skirt that costs 32.00. she pays 10% sales tax. how much does she pay for the dress, with tax
Olenka [21]

Answer:

$35.2 dollars

Step-by-step explanation:

You divide 10 by 32.00 and whatever that number equals, you add to 32.00:) Ta da! Hope this helps

5 0
4 years ago
John Muir was an American naturalist born in Scotland on April 21, 1838. As one of the first advocates of the United States' wil
lys-0071 [83]

Answer:

Step-by-step explanation:

Part A:

Mount Everest Great Himalayas of southern Asia 8,849.87 meters

In scientific notation

8.84987 * 10 ^3

Rounding to the nearest whole number

9 * 10 ^3

Mount Olympus Mytikas, Greece 2,919.07 meters

In scientific notation

2.91907 * 10 ^3

Rounding to the nearest whole number

3 * 10 ^3

Taking Everest and diving by Olympus

9 * 10 ^3÷3 * 10 ^3 = 9/3 *  10 ^ (3-3) = 3

3 times

Part B:

Mount Everest Great Himalayas of southern Asia 8,849.87 meters

In scientific notation

8.84987 * 10 ^3

Mount Olympus Mytikas, Greece 2,919.07 meters

In scientific notation

2.91907 * 10 ^3

Taking Everest and diving by Olympus

8.84987 * 10 ^3÷2.91907 * 10 ^3

8.84987/2.91907  * 10^(3-3) = 3.031742987

Part C:

The estimate is reasonable.  The estimate of 3 is very close to the value of 3.031742987   Therefore, we can conclude that the estimates for the heights were accurate.

4 0
3 years ago
Read 2 more answers
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