Answer:
90 90909090909090909090909090
Answer:
D. All three functions have the same minimum value
Step-by-step explanation:
f(x) = -3 sin (x-pi) +2
Sin has a minimum value of -1, but since it is multiplied by a negative, we want its maximum value
sin has a maximum of 1
f (min) = -3(1) +2 = -1
g(x) has a minimum at x =3
g(minimum) = -1
h(x) = (x+7)^2 -1
The smallest a squared value can be is zero
= 0 -1
h(min) =-1
You know 1 is not a root because the sum of the coeffcients of the equation is 14, not zero.
It is fairly easy to try 3 by synthetic division (see attachment), which tells you that 3 is a root and the remaining quadratic factor is x²-3x-5. The quadratic formula tells you the roots of that factor are
... x = (-b±√(b²-4ac))/(2a) = (3±√29)/2
The appropriate choices are
... C. (3-√29)/2
... D. (3+√29)/2
... F. 3
_____
The quadratic formula tells you the solution to
... ax²+bx+c=0
is x = (-b±√(b²-4ac))/(2a)
We have a=1, b=-3, c=-5.
You have to make the denominators (bottom numbers) the same via multiplication, it's best to do it to the first number they meet at. that would be fifteen (15)
5×3=15
3×5=15
you then have to multiply the numerators by the respective numbers.
2×3=6
1×5=5
you then subtract the numerators normally
6-5=1
slap back on the denominator
1/15
there's your answer.
(the number you multiply them by isn't the other denominator, it just happens to be the denominators for this equation)
