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dolphi86 [110]
3 years ago
13

Over which interval(s) is the function decreasing?

Mathematics
1 answer:
mart [117]3 years ago
7 0

Answer:

<u>B.(-5.5; 0)</u>

Step-by-step explanation:

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Please answer this correctly
crimeas [40]

Answer:

2/3

Step-by-step explanation:

Numbers greater than 2 on a 6-sided dice are 3, 4, 5, and 6.

4 possibilities out of 6.

4/6 = 2/3

7 0
3 years ago
Read 2 more answers
Simplify the question. 1/4g plus 6g minus 2/3
MatroZZZ [7]
1/4+6-2/3
3/12+72/12-8/12
75/12-8/12
67/12 
or 
.25+6-.66
6.25-.66
5.59


3 0
3 years ago
I’ll mark brainlest
Alla [95]

Answer:

48,841,380.8

Step-by-step:

find 12% of 14,365,112= 1,723,813.44

then find 1,723,813.44×20= 34,476,268.8

then 34,476,268.8+14,365,112=48,841,380.8

3 0
3 years ago
Read 2 more answers
each pizza has found out that each pizza has 12 slices. you expect 16 people to come, you estimate that each person will eat 3 s
konstantin123 [22]

Answer:

We will get 4 pizza.

Step-by-step explanation:

Each person will eat 3 slices of pizza and we are expecting 16 people to come.So total number of slices consumed by 16 people will be

16×3 = 48 slices.

Now it is given in the question that each pizza has 12 slices then we have to find out number of pizza to be ordered.

We apply unitary method

∵ 12 slices will be = 1 pizza

∴ 1 slice will be = 1/12 pizza

∴ 48 slices will be = 1/12×48

                              =48/12

                              = 4 pizza

So total 4 pizza to be ordered.

8 0
3 years ago
Read 2 more answers
Finally, suppose m1→∞, while m2 remains finite. what value does the the magnitude of the tension approach?
Anna007 [38]
The answer is not infinity. 
<span>Consider FBDs of each mass with the direction of motion of m1 as positive </span>

<span>m1*g-T=m1*a </span>

<span>T-m2*g=m2*a </span>

<span>assuming mass less cord and mass less, friction less pulley </span>
<span>the accelerations are equal </span>
<span>a=(T-m2*g)/m2 </span>

<span>m1*g-T=m1*(T-m2*g)/m2 </span>
<span>do some algebra </span>
<span>m1*g-T=m1*T/m2-m1*g </span>
<span>2*m1*g=T*(1+m1/m2) </span>
<span>2*m1*m2*g=T*(m2+m1) </span>
<span>2*m1*m2*g/(m2+m1)=T </span>
<span>now take the limit of T as m1->infinity </span>
<span>T=2*m2*g </span>

<span>this is intuitively correct since the maximum acceleration of m1 is -g, the cord transfers the acceleration to m2, which is being acted on by gravity downward and an upward acceleration of g. Therefore the maximum acceleration of m1 is 2*g upward. </span>
5 0
3 years ago
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