Answer:
Hi, for this exercise we have two laws to bear in mind:
Morgan's laws
NOT(А).NOT(В) = NOT(A) + NOT (B)
NOT(A) + NOT (B) = NOT(А).NOT(В)
And the table of the Nand
INPUT OUTPUT
A B A NAND B
0 0 1
0 1 1
1 0 1
1 1 0
Let's start!
a.
Input OUTPUT
A A A NAND A
1 1 0
0 0 1
b.
Input OUTPUT
A B (A NAND B ) NAND (A NAND B )
0 0 0
0 1 0
1 0 0
1 1 1
C.
Input OUTPUT
A B (A NAND A ) NAND (B NAND B )
0 0 0
0 1 1
1 0 1
1 1 1
Explanation:
In the first one, we only need one input in this case A and comparing with the truth table we have the not gate
In the second case, we have to negate the AND an as we know how to build a not, we only have to make a nand in the two inputs (A, B) and the make another nand with that output.
In the third case we have that the OR is A + B and we know in base of the morgan's law that:
A + B = NOT(NOT(А).NOT(В))
So, we have to negate the two inputs and after make nand with the two inputs negated.
I hope it's help you.
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so this means its more basic antagonist protagonist set-up even if the protagonist and antagonist are "CUBES"</span>
Answer:
(3) option is the correct answer.
Explanation:
Constructors need to initialize the object in the memory. "To declare the Constructor for any class the user needs to specify the constructor name which is already the class name". This is an object-oriented language guideline.
It is because the object is created by the name of the class and Constructor is used to allocate the memory for the object. hence Constructor is created by the name of the class.
For example--
class test //class name test
{
test() //created a constructor with class name "test"
{
}
}
In the above example class name and constructor name are same if it not then it will gives a error.
Another option is not valid for the answer to the above problem because-
- Option 1 is wrong because, for any class, the data member is a type of variable, which is used to store the data and is accessed with the help of an object.
- Option 2 is wrong because, for any class, member function is a type of user function used to accessed the variable and expressions.
- Option 4 is wrong because, package is a set used to hold classes and interfaces.
Answer:
dataFile << salary;
Explanation:
To write salary to a file (payroll.dat) using ofstream, you make use of the following instruction:
<em>ofstream dataFile;
</em>
<em>myfile.open ("payroll.dat");
</em>
<em>myfile <<salary;
</em>
<em>myfile.close();</em>
<em />
This line creates an instance of ofstream
<em>ofstream dataFile;
</em>
This line opens the file payroll.dat
<em>myfile.open ("payroll.dat");
</em>
This is where the exact instruction in the question is done. This writes the value of salary to payroll.dat
<em>myfile <<salary;
</em>
This closes the opened file
<em>myfile.close();</em>
<em />
<em />
Answer:
CLS
INPUT"Enter any three numbers";a,b,c
IF a>b AND a>c THEN
PRINT a;"is the greatest"
ELSEIF b>a AND b>c THEN
PRINT b;"is the greatest"
ELSE
PRINT c;"is the greatest"
ENDIF
END
