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4 years ago

38% income tax on an income of $80,000

Mathematics

2 answers:

posledela4 years ago

8 0

38% of income tax on an income of $80,000 would be $30,400

antiseptic1488 [7]4 years ago

8 0

$80000×38%=$30400. As a result, the income tax is $30400. Hope it help!

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The speed of radio waves can be approximated to be 299,790,000 meters per second. The wavelength of a particular radio station’s

azamat

Answer:

$f = \frac{299790000 \frac{m}{s}}{3.03 m}= 9890594.06 Hz$

And if we convert to megahertz we got:

$9890594.06 Hz *\frac{1MHz}{10^6 Hz}= 98.9 MHz$

Step-by-step explanation:

For any mechanical wave we have the following general relationship:

$v = \lambda f$

where:

v represent the speed of the wave = 299790000 m/s

$\lambda = 3.03m$ represent the wavelength for the radio station

f represent the frequency of interest

If we solve for the frequency we got:

$f = \frac{v}{\lambda}$

And replacing the values we got:

$f = \frac{299790000 \frac{m}{s}}{3.03 m}= 9890594.06 Hz$

And if we convert to megahertz we got:

$9890594.06 Hz *\frac{1MHz}{10^6 Hz}= 98.9 MHz$

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3 years ago

HELLLLP (will mark brainiest)

Zigmanuir [339]

Answer:

We put the value of the x in the formula

${4 \times }(6)^{2} - 7 \times 6 + 12$

f(6)=

$4 \times 36 - 7 \times 6 + 12 = 144 - 42 + 12 = 102 + 12 = 114$

Step-by-step explanation:

Than solve equation.

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3 years ago

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Plzz i will give brainliest if correct plzzzzzzzzzzzzzzz

GuDViN [60]

Answer:

Umm what do <em>I</em> answer there is nothing there

Step-by-step explanation:

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3 years ago

The probability that a lab specimen contains high levels of contamination is 0.10. A group of 4 independent samples are checked.

galben [10]

Answer:

a) 0.6561

b) 0.2916

c) 0.3439

Step-by-step explanation:

We are given the following information:

Let us treat high level of contamination as our success.

p = P(High level of contamination) = P(success) = 0.10

n = 4

The, by binomial distribution:

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}\\\text{where x is the number of success}$

a) P(No high level of contamination)

We put x = 0, in the formula.

$P(X=0) = \binom{4}{0}.(0.10)^0.(1-0.10)^{4} =0.6561$

Probability that no lab specimen contain high level of contamination is 0.6561

b) P(Exactly one high level of contamination)

We put x = 1, in the formula.

$P(X=1) = \binom{4}{1}.(0.10)^1.(1-0.10)^{3} =0.2916$

Probability that no lab specimen contain high level of contamination is 0.6561

c) P(At least one contains high level of contamination)

$p(x \geq 1) = 1 - p( x = 0) = 1 - 0.6561 = 0.3439$

Probability that at least 1 lab specimen contain high level of contamination is 0.3439

8 0

3 years ago

Help plz:)!!!!!!!!!!!!

solmaris [256]

Answer:first one
hope this helps

5 0

3 years ago

Read 2 more answers