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3 years ago

If a roasting is 600mm x 500mm how many 25cm cake time will fit on it?

1 answer:

3 0

So assuming that 25cm is 25 square cm because you cannot have a 2 dimentional cake so

600mm by 500mm
to find the area, multiply legnth by width

mm=milimeters
cm=centimeters
this is in mm so
1cm=10mm
1mm=1/10cm
to convert from mm to cm, you divide by 10
we must divide by 10 first
legnth =600mm
600/10=60cm
legnth=60cm

width=500mm
500/10=50cm
width=50cm

area=60 times 50=3000 square cm or cm^2
so 3000 is the area
25 is the area of each cake
divide 3000 into 25 and find how many cakes will fit

3000/25=120

120 cakes will fit

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Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o

Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is $\hat p_1$ = 1020/1272 = 85/106 = $0.8\overline {0188679245283}$ ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is $\hat p_2$ = 5343/6238 ≈ 0.8565

c) We have the following two way table;

$\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}$

$The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780$

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

$95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}$

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

$95 \% \ CI \approx 0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155$

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0

3 years ago

According to the fundamental theorem of algebra, how many zeros does the function f(x) = 15x17 + 41x12 + 13x3 − 10 have?

liberstina [14]

The fundamental theorem of algebra states that a polynomial of degree has exactly n roots (including complex and multiple).
The degree of a polynomial is the highest (non-negative) exponent of the polynomial, in this case is 17 from the term 15x^17.

3 0

3 years ago

Read 2 more answers

Select the correct answer. What is the surface area of the victory podium shown here? Include all surfaces of the podium, includ

Leya [2.2K]

Answer:

Option C is correct.

Step-by-step explanation:

Given the dimension of the surfaces i.e length, width and height of podium. we have to calculate the surface area of the victory podium.

As Surface area of cuboid is 2(LW+WH+HL)

In the given figure, the upper cuboid has dimension

L=2.5 ft. , W=1.5 ft, H=1.5 ft

$\text{Surface area=}2(2.5(1.5)+1.5(1.5)+1.5(2.5))=19.5ft^2$

$\text{Area of bottom face of upper cuboid=}L\timesW=2.5\times1.5=3.75ft^2$

The upper face is occuring twice therefore it must be subtracted to find the area

Dimensions of lower podium are

L=7.5 ft. , W=1.5 ft, H=1.5 ft

$\text{Surface area=}2(7.5(1.5)+1.5(1.5)+1.5(7.5))=49.5ft^2$

Now, Surface area of podium included bottom is

19.5+49.5-3.75=65.25 square feet.

Hence, option C is correct.

4 0

3 years ago

Solve the inequality

Lana71 [14]

3x-12>15
3x>15+12
3x÷3>27÷3
x>9

7 0

3 years ago

Mark owns Siberian Husky sled dogs. He knows from data collected over the years that the weight of the dogs is a normal distribu

kozerog [31]

Calculate the z-score for the given data points in the item using the equation,

z-score = (x - μ) / σ

where x is the data point, μ is the mean, and σ is the standard deviation.

Substituting,
(47.7) z-score = (47.7 - 52.5)/2.4 = -2

This translates to a percentile of 2.28%.

(54.9) z-score = (54.9 - 52.5)/2.4 = 1

This translates to a percentile of 84.13%.

Then, subtract the calculate percentiles to give us the final answer of <em>81.85%.</em>

Thus, 81.85% of the Siberian Husky sled dogs are expected to weigh between 47.7 and 54.9 lbs.

8 0

3 years ago