a ship sails 20km due north. It changes direction and then sails 15 due east. How far is it from its starting point?
1 answer:
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Answer:
Step-by-step explanation:
Hello!
The variable of interest is
X: production cost of a major move
Its average is μ= 65 million dollars, and standard deviation σ= 18 million dollars.
a)
This variable has a normal distribution X~N(μ;σ²)
X~N(65;324)
b)
The distribution of the sample mean has the same shape as the distribution of the variable, but its variance is affected by the sample size:
~N(μ;σ²/n) ⇒
~N(65;8.3077)
σ²/n= 324/39= 8.30769≅ 8.3077
c)
You have to calculate the probability of a single movie costing between 69 and 66 million dollars, symbolically:
P(66≤X≤69)= (X≤69)-P(X≤66)
You have to use the standard normal distribution to calculate this probability, so first you have to calculate the Z values that correspond to each value of X using: Z= (X-μ)/σ ~ N(0;1)
Z₁= (69-65)/18= 0.22
Z₂=(66-65)/18= 0.05
Now you look for the corresponding probability values using the standard normal table
P(Z≤0.22)= 0.58706
P(Z≤0.05)= 0.51994
P(66≤X≤69)= (X≤69)-P(X≤66)
P(Z≤0.22)-P(Z≤0.05)= 0.58706 - 0.51994= 0.06712
d)
Now you have to calculate the probability of the average production cost to be between 69 and 66 million. Since the probability is for the average value of the sample, you have to work using the distribution of the sample mean. The values od Z are to be calculated using the formula Z= (-μ)/(σ/√n)
σ/√n= 2.8823
P(66≤≤69)= (
≤69)-P(
≤66)
Z₁= (69-65)/2.8823= 1.387= 1.39
Z₂= (66-65)/2.8823= 0.346= 0.35
P(Z≤1.39)-P(Z≤0.35)= 0.91774 - 0.63683= 0.28091
e)
No
If the variable has an unknown or non-normal distribution, but the sample is large enough (normally a sample n≥30 is considered to be large) you can apply the central limit theorem and approximate the sampling distribution to normal.
I hope this helps!
Answer:
The number of girls participated in quiz is 40 .
Step-by-step explanation:
Given as :
Total number of students took quiz = 100
Average score of 100 students = 76 points
The Average score of boys = 80 points
The Average score of girls = 70 points
Let The number of boys participated in quiz = b
Let The number of girls participate in quiz = g
Now, According to question'
Total number of students took quiz = number of boys participated in quiz + number of girls participated in quiz
Or, b + g = 100 ........A
<u>Again</u>
∵ Average score of 100 students = 76 points
∴ Total score of 100 students = 76 × 100 = 7600
So, Average score of boys × number of boys participated + Average score of girls × number of girls participated = Total score of 100 students
Or, b × 80 + g × 70 = 7600
Or, 80 b + 70 g = 7600 .........B
Now, Solving equation A and B
(80 b + 70 g ) - 70 ×( b + g ) = 7600 - 70 × 100
I.e (80 b - 70 b) + (70 g - 70 g) = 7600 - 7000
Or, 10 b + 0 = 600
∴ b =
i.e b = 60
So, The number of boys participated in quiz = b = 60
Put the value of b into eq A
∵ b + g = 100
So, g = 100 - b
Or, g = 100 - 60
i.e g = 40
So, The number of girls participated in quiz = g = 40
Hence, The number of girls participated in quiz is 40 . Answer