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geniusboy [140]
3 years ago
9

Which statement about the ordered pairs (−9, 3) and (2, −4) is true for the equation 6x−y2=14 ?

Mathematics
1 answer:
Komok [63]3 years ago
8 0
Neither ordered pair is a solution.
If you solve y^2-6y + 14 = 0 you'll see by the discriminate b^2-4ac
that it is not a perfect square, i.e = -20, so the solutions are imaginary numbers, i.e. no real solutions.
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