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Vera_Pavlovna [14]
3 years ago
14

Which expression is equivalent to 2 (14x-3y+28x+12.2-5y-17.5)?

Mathematics
2 answers:
scoundrel [369]3 years ago
7 0

To find the equivalence you need to simplify the expression to get

84x - 16y - 10.6

:)))

Oduvanchick [21]3 years ago
3 0

Answer:

Equivalent Expression of given Expression is 84x - 16y - 10.6.

Step-by-step explanation:

Given Expression is :

2(14x-3y+28x+12.2-5y-17.5)

We have to find: Equivalent Expression

To find Equivalent expression we simplify the given expression.

Consider,

2(14x-3y+28x+12.2-5y-17.5)

Group like terms,

\implies2(14x+28x-3y-5y+12.2-17.5)

Now solve like terms,

\implies2(42x-8y-5.3)

Now, using Distributive Property

\implies2\times42x-2\times8y-2\times5.3

\implies84x-16y-10.6

Therefore, Equivalent Expression of given Expression is 84x - 16y - 10.6.

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Answer:

1. $427.50

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Step-by-step explanation:

1. First, find your salary at minimum hours, which is $360. Then, take your second equation, plug in 45, and solve using PEMDAS. This will give you $427.50

2. To solve this, you'll need to set it up like so:

495 = 13.5 (x - 40) + 360

Your next step will be to distribute the number outside the parentheses. This will give you:

495 = 13.5x - 540 + 360

Simplify, like so:

495 = 13.5x - 180

Solve.

495 = 13.5x - 180

+180             +180

This will give you:

675 = 13.5x

Divide each side.

675 = 13.5x

------    -------

13.5     13.5

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Step-by-step explanation:

According to the divergence test, for an infinite series ∑ aₙ, the series diverges if lim(n→∞) aₙ ≠ 0.

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Step-by-step explanation:

Part 10)

step 1

Find the length of side EG

see the attached figure to better understand the problem

we know that

In the right triangle EGF

cos(65^o)=\frac{EG}{EF} ----> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

cos(65^o)=\frac{EG}{11}

solve for EG

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step 2

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