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koban [17]
3 years ago
10

Mr. Meyer bought a block of fudge that weighed 1/2 of a pound. He cut the fudge into 5 equal pieces. What was the weight of each

piece of fudge?
Mathematics
1 answer:
almond37 [142]3 years ago
5 0

Answer:

2.5 lb

Step-by-step explanation:

You might be interested in
-4x 3y = -2<br><br> y = x -1
MA_775_DIABLO [31]

Answer:

The answer is:  X= -1 and y= -2 so <em><u>(-1,-2)</u></em>

hope this helps

5 0
2 years ago
Mouza, Alreem, Latifa, Zayed and Mohammed are
julia-pushkina [17]

Answer:

900m

Step-by-step explanation: if one is 300m then do 300m x 3 =900m.

Hoped this help

7 0
2 years ago
An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
2 years ago
Solve for 6y+12=3y-3
kherson [118]
6y + 12 = 3y - 3

Subtract 3y on both sides

3y + 12 = -3

Subtract 12 on both sides

3y = -15

Divide by 3 on both sides

y = -5
5 0
3 years ago
Read 2 more answers
Write riddle for the number 62
EastWind [94]
A number between 60 & 65 ??
5 0
3 years ago
Read 2 more answers
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