if Chelsea has 11 times as many art. Brushes and they have 60 art brushes altogether how many brushes does Chelsea have

1 answer:

8 0

<span>t's call P the number of art brushes that Monique has. Chelsea has 11xP (that is 11 times as many as Monique) Together they have: P + 11xP = 12xP That means 12xP = 60 (60 is the number of art brushes they have together) In order to find how much is P, we need to divide: 60 Ă· 12 = 5 brushes P = 5 ; that means has Monique 5 art brushes. Chelsea has 11 times as many art brushes as Monique: 11 x 5 = 55 brushes</span>

You might be interested in

H(x) = x3 + 7<br> Determine whether the function is one-to-one.

zubka84 [21]

Answer:

we conclude that the function is one-to-one.

Step-by-step explanation:

A function will a one-to-one function if it

passes the vertical line test to make sure it is indeed a function, and

also a horizontal line test to make sure it is it one-to-one.

In other words,

The function will be one-to-one if it passes the vertical line test, and also if the horizontal line only cuts the graph of the function in one place.

The reason is that there must be only one x-value for each y-value.

Given the function

$h\left(x\right)\:=\:x^3\:+\:7$

Have a look at the attached graph.

The red portion represents the graph of the function $h\left(x\right)\:=\:x^3\:+\:7$ .

The green portion represents the graph of x=2 which is basically a vertical line test. Vertical line indicates that it cuts the cuts the graph of the function in one place. So it is clear that $h\left(x\right)\:=\:x^3\:+\:7$ is indeed a function.

The blue line represents the graph of y=9, which is basically a horizontal line test. Horizontal line indicates that it cuts the cuts the graph of the function in one place. So it is clear that $h\left(x\right)\:=\:x^3\:+\:7$ is a one-to-one function, as there is only one x-value for each y-value.

Therefore, we conclude that the function is one-to-one.

6 0

3 years ago

[PLEASE ANSWER BOTH QUESTIONS] The following data points represent the number of quesadillas each person at Toby's Tacos ate. So

Fynjy0 [20]

Answer:

Part 1: Already solved.

Part 2: 1 quesadilla.

Step-by-step explanation:

Part 1: The data points given are 0, 0, 1/4, 1/2, 1/2, 1, 1, 1, 5/4, 2, and 2.

The data are already sorted from least to greatest.

Part 2: To get the interquartile range, we must know the first and third quartiles. To find those, we need to know the median of the data.

There are 11 data points, so we can cross out 5 numbers on the left and cross out 5 numbers on the right. That leaves a median of 1.

Since we know the median is 1, we can find the first quartile by finding the median of the following numbers: 0, 0, 1/4, 1/2, 1/2 (any number less than 1). There are five numbers, so cross out two numbers from the left and cross out two numbers from the right. We are left with a first quartile of 1/4.

Now that we have the first quartile, we need to find the third quartile. Since the median was actually the first "1" in the data set, the third quartile will be the median of the numbers to the right of that "1": 1, 1, 5/4, 2, 2. Cross out the leftmost two numbers, and cross out the rightmost two numbers. We are left with a third quartile of 5/4.

Now that we have both the third and first quartiles, we can find the interquartile range! The IQR is calculated by finding the third quartile minus the first quartile. 5/4 - 1/4 = 4/4 = 1.

So, your interquartile range is 1 quesadilla.

Hope this helps!

5 0

3 years ago

Read 2 more answers

Expand the following:<br> a) 3(x + 5)<br> b) 4(x-4)<br> c) 2(5x + 1)<br> d) 7(x-9y)

Tema [17]

Answer: