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2 years ago

Which data set is represented by the modified box plot 92,88,100,136,106,79,88,86,98,115

Mathematics

1 answer:

Vera_Pavlovna [14]2 years ago

8 0

Answer:

One dot mark above one hundred and thirty-six. A) 92, 88, 100, 136, 106, 79, 88, 86, 98, 115. B) 92, 88, 100 ...

Step-by-step explanation:

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Evaluate the expression when a=-7 and c=6. a-6c

beks73 [17]

Answer:

-43

Step-by-step explanation:

(-7) - 6(6)= -43

4 0

2 years ago

Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl

amm1812

Answer:

1. $P(s_1|I)=\frac{1}{11}$

2. $P(s_2|I)=\frac{8}{11}$

3. $P(s_3|I)=\frac{2}{11}$

Step-by-step explanation:

Given information:

$P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3$

$P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1$

(1)

We need to find the value of P(s₁|I).

$P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}$

$P(s_1|I)=\frac{0.015}{0.165}$

$P(s_1|I)=\frac{1}{11}$

Therefore the value of P(s₁|I) is $\frac{1}{11}$ .

(2)

We need to find the value of P(s₂|I).

$P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}$

$P(s_2|I)=\frac{0.12}{0.165}$

$P(s_2|I)=\frac{8}{11}$

Therefore the value of P(s₂|I) is $\frac{8}{11}$ .

(3)

We need to find the value of P(s₃|I).

$P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}$

$P(s_3|I)=\frac{0.03}{0.165}$

$P(s_3|I)=\frac{2}{11}$

Therefore the value of P(s₃|I) is $\frac{2}{11}$ .

4 0

2 years ago

11. Which of the following best describes the range of

Gnoma [55]

Answer:

D. All real numbers

Step-by-step explanation:

The range of a function is all of the possible x-values (which is easiest to understand if you can view a graph), and the domain of a function is all possible y-values.

So, you could put any x-value into this function (and it would have a corresponding y-value)

The domain [y] is limited, but the range [x] is best described as all real numbers

(if it's hard to remember which is which, d comes before r alphabetically, and x comes before y alphabetically)

7 0

1 year ago

Let U=5i-9j and V=-8i+8j. find U-V

liraira [26]

$U-V\\
5i-9j-(-8i+8j)=0
\\5i-9j+8i-8j=0
\\13i-17j=0$
is your final answer.

5 0

3 years ago

Please Help Will Mark Brainliest

bearhunter [10]

Answer:

the way i put these numbers is the way the numbers go on the chart

15 25 25 65

10 5 20 35

25 30 45 100

Step-by-step explanation:

3 0

2 years ago

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