Answer
Step-by-step explanation:
because all you have to do is look at the total after "car".
Answer:
kflhddddddddddddnbhpppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp
Step-by-step explanation:
Answer:
The probability that Actuary Rahul examines fewer policies that Actuary Toby = 0.2857
Step-by-step explanation:
It is said that Actuary Rahul examines a low risk policy
Probability of a low risk policy having a claim = 10% = 0.1
Actuary Toby examines high risk policy
Probability of a high risk policy having a claim = 20% = 0.2
Let the number of policies examined by actuary Rahul before he finds a claim and stop be n
Probability that actuary Rahul examines exactly n policies = 
Probability that Toby examines more than n policies = 
Since the claim statuses of policies are mutually independent, the probability that both events happen simultaneously = 
probability that both events happen simultaneously = 
The probability that Actuary Rahul examines fewer policies that Actuary Toby =
= 
The probability that Actuary Rahul examines fewer policies that Actuary Toby = 0.2857
8/(3/4) = 8*(4/3) = 32/3 = 10 2/3
There are 10 servings of 3/4 cup
.. with 1/2 cup of berries left over.
Here's a way to do it.
Let 4e +2 = 5n +1 . . . . . . for some integer n
Then e = (5n -1)/4 = n + (n -1)/4
We want (n-1)/4 to be an integer, so let it be integer m.
... m = (n -1)/4
... 4m = n -1
... 4m +1 = n
Substituting this into our expression for e gives
... e = (5(4m+1) -1)/4 = (20m +4)/4 = 5m +1
e = 5m+1 for any integer m