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kogti [31]
3 years ago
11

Can i have some help with this please?

Mathematics
2 answers:
Zepler [3.9K]3 years ago
3 0
This will be the answer

Travka [436]3 years ago
3 0

Answer:

y = - \frac{2}{7} x + 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - \frac{2}{7} and c = 5, thus

y = - \frac{2}{7} x + 5 ← equation of line

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Somebody please help me
WITCHER [35]

Step-by-step explanation:

x - 1 = - 3x - 14

Bringing like terms on one side

x + 3x = -14 + 1

4x = - 13

x = - 13/4

5 0
2 years ago
18. What is the y-intercept of the line that passes<br> through the points (1, 1) and (5, 13)?
TEA [102]

Answer:

-2

(The coordinate point is (0,-2))

Step-by-step explanation:

First, make an equation of the line.

Start off with finding the slope:

Slope = (13-1)/(5-1) = 12/4 = 3

Then solve for the y-intercept though substitution and simplification:

y=mx+b --> 1=3(1)+b --> 1=3+b --> b= -2

So the answer is -2.

4 0
3 years ago
What is the sum of 3/4 + 5/16
guapka [62]
3/4 + 5/16
=12/16 +5/16
=17/16
=1 1/16
4 0
3 years ago
Read 2 more answers
2z -5(z +2) = -8 - 2z<br><br> Please explain!! Thank you
Korolek [52]

Follow PEMDAS.

You would first do your distributive property which is, -5(z+2). You would multiply -5 to z and -5 to 2 which will give you -5z + -10.

so now you have 2z-5z+ -10= -8 - 2z. Now you must isolate the variable. So subtract -8 to -10 which will give you -18.

Now you have the equation 2z-5z-18=-2z

Now combine like terms. 2z-5z= -3z

Now you have the equation -3z-18=-2z

Now you must move the -3z to the other side of the equal sign by adding the opposite which is +3z to -2z which will give you +1z

Now you have -18= 1z

Now you divide. -18 divided by 1 is -18.

So your final answer will be -18=z

7 0
3 years ago
A bank records deposits as positive numbers and withdrawals as negative numbers. Mike withdrew $60\$60 $60 dollar sign, 60 from
kumpel [21]

Answer:

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Step-by-step explanation:

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------

8 0
3 years ago
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