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Leona [35]
4 years ago
6

Why is the inequality is o equillant To The inequality x-5€6-5?

Mathematics
1 answer:
ser-zykov [4K]4 years ago
4 0

Answer:

fi9ovdfv8u9reiovre8ckl

Step-by-step explanation:

caeerqvf3e-=qrfvrqfeqcmijkcqerv=c

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Given the following functions f(x) and g(x), solve f over g (−5) and select the correct answer below:
ahrayia [7]
Plug -5 into both of them and divide:

\sf\dfrac{2x-20}{x-1}

\sf\dfrac{2(-5)-20}{-5-1}

Simplify:

\sf\dfrac{-10-20}{-6}

\sf\dfrac{-30}{-6}

\boxed{\sf 5}
7 0
3 years ago
Read 2 more answers
the price of a laptop including 6% tax is $2003.40.what is the price of the laptop excluding the tax?
devlian [24]
1.06*x=2003.40. So x=2003.4/1.06=1890.
3 0
3 years ago
How to find vertical and horizontal asymptotes of polynomials?
guajiro [1.7K]
Vertical asymptotes are when y tends to infinity, which in other words means you need a fraction where you're dividing by zero. So to find the vertical asymptotes, solve the denominator of the fraction and the solutions are the asymptotes since that is where it will be dividing by zero.

Horizontal asymptotes are the opposite and is where x tends to infinity -- This can be done by dividing through with the xs still there, since you are effectively just looking at multiples of infinity and infinity squared and so on. When you have an x to the power you can forget about all the other x's on the same half of the fraction, since infinity squared is infinitely bigger than infinity - yes it's abstract and a bit stupid I know.
If the degree of the polynomial on the denominator is larger than the numerator, there is an asymptote at y=0 (since the bottom becomes infinitely larger than the top). If it is lower than the numerator, you have to divide through by long division and you end up with an oblique asymptote i.e. an asymptote where the dotted line would follow a linear equation e.g. y=x

For example
f(x)= \frac{6x^2-3x+4}{2x^2-8}

The vertical asymptote can be found by solving 2x^2-8=0 i.e. x=+-2 so our vertical asymptotes are at 2 and -2.

The horizontal asymptote, think of all the x's as infinity. SInce there are x^2s, we dont need to worry about the numbers or the other x's
Therefore we are left with 6x^2/2x^2, which gives us 3. Therefore our horizontal asymptote would be at y=3.
7 0
3 years ago
Is number 4 right? please explain how you do these types of problems
Fantom [35]

Answer:

No

Step-by-step explanation:

I haven't learned this but my brother says its incorrect, he is in Highschool, though he doesn't use Brainly.

4 0
3 years ago
Read 2 more answers
A sample of 8 new models of automobiles provides the following data on highway miles per gallon. Highway Miles Model Per Gallon
Furkat [3]

Answer:

The point estimate for the mean is 29.5 miles per gallon and the standard deviation is 5.9

Step-by-step explanation:

The formula por the point estimate of the mean is:

mean(x) = \frac{x1+x2+x3+...+xn}{n}

And for the standard deviation:

desv(x)=(\frac{1}{n-1}sum(xi^{2} - n*x^{2} ))^{1/2}

So for the mean:

mean(x)=\frac{33.6+26.8+20.2+38.7+35.1+28.0+26.2+27.6 }{8} \\\\mean(x)=\frac{236.2}{8} \\\\mean(x)=29.5

And for the standard deviation:

desv(x)=(\frac{1}{8-1} ((33.6-29.5)^{2} +(26.8-29.5)^{2} +(20.2-29.5)^{2} +(38.7-29.5)^{2} +(35.1-29.5)^{2} +(28-29.5)^{2} +(26.2-29.5)^{2} +(27.6-29.5)^{2})^{1/2} \\\\desv(x)=(\frac{1}{8-1} ((4.1)^{2} +(-2.7)^{2} +(-9.3)^{2} +(9.2)^{2} +(5.6)^{2} +(-1.5)^{2} +(-3.3)^{2} +(-1.9)^{2})^{1/2} \\\\desv(x)=\sqrt{\frac{243.3}{7}} \\\\desv(x)=\sqrt{34.7} \\\\desv(x)=5.9

5 0
4 years ago
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