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svetlana [45]
3 years ago
9

Need help finding the x-intercept zeros for x(x+2) (x-2)^2

Mathematics
1 answer:
miskamm [114]3 years ago
6 0
X= 0 (multiplicity of 1)
X= -2 (multiplicity of 1)
X= 2 (multiplicity of 2)
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A marketing firm would like to test-market the name of a new energy drink targeted at 18- to 29-year-olds via social media. A st
Anon25 [30]

Answer:

(a) The probability that a randomly selected U.S. adult uses social media is 0.35.

(b) The probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c) The probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = an US adult who does not uses social media.

<em>Y</em> = an US adult between the ages 18 and 29.

<em>Z</em> = an US adult between the ages 30 and above.

The information provided is:

P (X) = 0.35

P (Z) = 0.78

P (Y ∪ X') = 0.672

(a)

Compute the probability that a randomly selected U.S. adult uses social media as follows:

P (US adult uses social media (<em>X'</em><em>)</em>) = 1 - P (US adult so not use social media)

                                                   =1-P(X)\\=1-0.35\\=0.65

Thus, the probability that a randomly selected U.S. adult uses social media is 0.35.

(b)

Compute the probability that a randomly selected U.S. adult is aged 18–29 as follows:

P (Adults between 18 - 29 (<em>Y</em>)) = 1 - P (Adults 30 or above)

                                            =1-P(Z)\\=1-0.78\\=0.22

Thus, the probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c)

Compute the probability that a randomly selected U.S. adult is 18–29 and a user of social media as follows:

P (Y ∩ X') = P (Y) + P (X') - P (Y ∪ X')

                =0.22+0.65-0.672\\=0.198

Thus, the probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

6 0
3 years ago
What is 34 x000 tell me please
Nataly_w [17]
Thirty four times 000 which I am assuming is just zeroes would be 0.
7 0
3 years ago
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I need help ASAP with this question
Ira Lisetskai [31]

\frac{7}{10} =\frac{7*4}{10*4}=\frac{28}{40}

\frac{3}{4} =\frac{3*10}{4*10} =\frac{30}{40}

As you can see:

\frac{28}{40}

\frac{7}{10}

7 0
3 years ago
What is the product of (5^-1)(5^-3)<br> A. 1/625<br> B.1/25<br> C.25<br> D.125
Mice21 [21]
The correct answer is A 
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Let A and B be nxn matrices such that AB is singular prove that either A or Bis singular
Alex_Xolod [135]
\det(\mathbf{AB})=\det\mathbf A\times\det\mathbf B

Because \mathbf{AB} is singular, we have

\det(\mathbf{AB})=0

from which it follows that either \det\mathbf A=0 or \det\mathbf B=0.
4 0
3 years ago
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