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3 years ago

What is the value of a in the equation a=3a + 12?

Mathematics

1 answer:

likoan [24]3 years ago

3 0

a = 3a + 12
- 3a - 3a
-2a = 12
-2 -2
a = -6

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2 boxes, 24 kgs each, 1000 items total, how many does each box have? What would be the system of equations?

Vaselesa [24]

500 each because there's only 2 boxes

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3 years ago

Solve 5a

arlik [135]

In order to solve this equation, try to get
the variable by itself. Begin by treating forgetting about 5 in 5a. This makes a/7=25. Multiply 7 and 25 to get 175, then place the 5 back in from of the a. Then divide 175 by 5a and get 35.

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4 years ago

A pro basketball player is a poorâ free-throw shooter. Consider situations in which he shoots a pair of free throws. The probabi

zlopas [31]

Answer:

The probability that he makes one of the two free throws is 0.38

Step-by-step explanation:

Hello!

Considering the situation:

A pro basketball player shoots two free throws.

The following events are determined:

A: "He makes the first free throw"

Ac: "He doesn't make the first free throw"

B: "He makes the second free throw"

Bc: "He doesn't make the second free throw"

It is known that

P(A)= 0.48

P(B/A)= 0.62

P(B/Ac)= 0.38

You need to calculate the probability that he makes one of the two free throws.

There are two possibilities, that "he makes the first throw but fails the second" or that "he fails the first throw and makes the second"

Symbolically:

P(A∩Bc) + P(Ac∩B)

Step 1.

P(A)= 0.48

P(Ac)= 1 - P(A)= 1 - 0.48= 0.52

P(Ac∩B) = P(Ac) * P(B/Ac)= 0.52*0.38= 0.1976≅ 0.20

Step 2.

P(A∩B)= P(A)*P(B/A)= 0.48*0.62= 0.2976≅ 0.30

P(A)= P(A∩B) + P(A∩Bc)

P(A∩Bc)= P(A) - P(A∩B)= 0.48 - 0.30= 0.18

Step 3

P(Ac∩B) + P(A∩Bc) = 0.20 + 0.18= 0.38

I hope this helps!

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3 years ago

4. State one use of the following gases: a) Argon - b) Helium -

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Step-by-step explanation:

HELIUM: To fill air balloon

ARGON: Used for filling incandescent metal filament electric bulbs

5 0

3 years ago

Plz solve this question Its too much urgent

Sergeu [11.5K]

Standard form of the polynomial is $x^{7}-2 x^{6}-3 x^{5}+x^{2}+\sqrt{2} x+4$ .

Degree of the polynomial is 7.

Solution:

Given polynomial:

$x^{7}-3 x^{5}+\sqrt{2} x+x^{2}-2 x^{6}+4$

To write this polynomial in standard form:

$x^{7}-3 x^{5}+\sqrt{2} x+x^{2}-2 x^{6}+4$

Standard form of the polynomial is writing x from highest power to lowest power.

Therefore, standard form of the polynomial is

$x^{7}-2 x^{6}-3 x^{5}+x^{2}+\sqrt{2} x+4$

Degree of the polynomial:

The highest power of x in the polynomial is the degree of the polynomial.

Here, the highest power is 7.

Hence the degree of the polynomial is 7.

3 0

3 years ago