The answer would be 37 I hope this helped
Complete Question
A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?
Answer:
The value required is
Step-by-step explanation:
From the question we are told that
The upper specification is 
The lower specification is
The sample mean is
The standard deviation is 
Generally the capability index in mathematically represented as
![Cpk = min[ \frac{USL - \mu }{ 3 * \sigma } , \frac{\mu - LSL }{ 3 * \sigma } ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%20%5Cfrac%7BUSL%20-%20%20%5Cmu%20%7D%7B%203%20%2A%20%20%5Csigma%20%7D%20%20%2C%20%20%5Cfrac%7B%5Cmu%20-%20LSL%20%7D%7B%203%20%2A%20%20%5Csigma%20%7D%20%5D)
Now what min means is that the value of CPk is the minimum between the value is the bracket
substituting value given in the question
![Cpk = min[ \frac{1.68 - 1.6 }{ 3 * 0.03 } , \frac{1.60 - 1.52 }{ 3 * 0.03} ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%20%5Cfrac%7B1.68%20-%20%201.6%20%7D%7B%203%20%2A%20%200.03%20%7D%20%20%2C%20%20%5Cfrac%7B1.60%20-%20%201.52%20%7D%7B%203%20%2A%20%200.03%7D%20%5D)
=> ![Cpk = min[ 0.88 , 0.88 ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%200.88%20%2C%200.88%20%20%5D)
So

Now from the question we are asked to evaluated the value of standard deviation that will produce a capability index of 2
Now let assuming that

So

=> 
=> 
So

=> 
Hence
![Cpk = min[ 2, 2 ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%202%2C%202%20%5D)
So

So
is the value of standard deviation required
Answer:
Two lines that intersect and form right angles are called perpendicular lines. The symbol ⊥ is used to denote perpendicular lines.
(5 + x) / 6 = -1....multiply both sides by 6, cancelling out the 6 on the left side
5 + x = -1 * 6
5 + x = -6
x = -6 - 5
x = -11
Answer:
1 in 8 chance.
Step-by-step explanation:
When a coin flips is has two outcomes: heads or tails, obviously.
Whenever you have a 50/50 probability, in this case a coin, every time you add another coin the amount of outcomes squares, or multiplies by the number of outcomes, and since we are using a coin, two. To reiterate, say we were using a die, a die is a cube, a six sided shape, so there are six outcomes. The chances of getting all sixes with one die is 1 in 6. Add another die and try to get all sixes, the chances become 1 in 36. We got this by multiplying our out comes by our outcomes
1 coin: 2 outcomes
2 coins: 4 outcomes
3 coins: 8 outcomes
Another thing:
Don't be fooled by questions being specific by saying "all heads" or "all tails"...
This is a wording trick, no matter the outcome, the chances will always be equal.
Good luck :)