Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
Explain whether the points (-13,4), (-7,3), (-1,2), (5,1). (11,0), (17, -1) represent the set of all the solutions for the
Nataly [62]
Answer:
ohh this is little bit hard
Step-by-step explanation:
Answer:
167 243/386
Step-by-step explanation:
For steps, use this link:
https://mathsolver.microsoft.com/en/solve-problem/64705%20%60div%20%20386
Answer:
$53.00 for 4 pounds
$13.25 for 1 pound
Step-by-step explanation:
Answer:
The smallest solution is -6
Step-by-step explanation:
2/3 x^2=24
Multiply by 3/2 on each side
3/2 *2/3 x^2=24 *3/2
x^2 = 36
Take the square root of each side
sqrt(x^2) = ±sqrt(36)
x = ±6
x = -6, 6
The smallest solution is -6
