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Anestetic [448]
3 years ago
9

A manufacturing process outputs parts having a normal distribution with a mean of 30 cm and standard deviation of 2 cm. From a p

roduction sample of 80 parts, what proportion of the sample can be expected to fall between 28 and 32 cm
Mathematics
1 answer:
Arisa [49]3 years ago
7 0

Answer:

68% of the sample can be expected to fall between 28 and 32 cm

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 30

Standard deviation = 2

What proportion of the sample can be expected to fall between 28 and 32 cm

28 = 30-2

28 is one standard deviation below the mean

32 = 30 + 2

32 is one standard deviation above the mean

By the Empirical Rule, 68% of the sample can be expected to fall between 28 and 32 cm

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Answer:

Shortest side = 39 cm.

Median side = 65 cm.

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Step-by-step explanation:

The perimeter in total is 195 cm. The ratio of the sides are 3 : 5 : 7.

First, find how much parts there are as a whole, by combining the ratios:

3 + 5 + 7 = 15 parts.

Divide the total of parts from the total measurement:

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Each part has the measurement of 13 cm.

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Use the following ratio to solve for each of the sides:

Shortest side: 3

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Median side: 5

5 x 13 = 65

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Check. Combine all side measurements together. They should equal 195:

39 + 65 + 91 = 195

(39 + 65) + 91 = 195

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195 = 195 (True).

~

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Step-by-step explanation:

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