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MrRa [10]
3 years ago
15

For the functions f(x)=−7x^2−x and g(x)=9x^2−4x, find (f−g)(x) and (f−g)(1)

Mathematics
1 answer:
musickatia [10]3 years ago
5 0

Answer:

See below.

Step-by-step explanation:

f(x)=-7x^2-x\\g(x)=9x^2-4x\\(f-g)(x)=f(x)-g(x)\\(f-g)(x)=(-7x^2-x)-(9x^2-4x)\\(f-g)(x)=-7x^2-x-9x^2+4x\\(f-g)(x)=-16x^2+3x\\\\(f-g)(1)=-16(1)^2+3(1)\\(f-g)(1)=-16+3=-13

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\frac{7}{10} |

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Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

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The two fractions now have like denominators so you can add the numerators.

Then:

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This fraction cannot be reduced.

The fraction 41/30

is the same as

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Convert to a mixed number using

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41/30 = 1 11/30

Therefore:

2/3+7/10= 1 11/30

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The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(41/30, -2/3) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

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The two fractions now have like denominators so you can add the numerators.

Then:

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This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 21 and 30 using

GCF(21,30) = 3

\frac{21/3}{30/3} =\frac{7}{10}

Therefore:

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