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aliina [53]
3 years ago
9

How do I do this problem?

Mathematics
1 answer:
Oduvanchick [21]3 years ago
8 0
4b+18\leq-12b-14\leq14-5b\\4b+18\leq-12b-14\,and\,-12b-14\leq14-5b\\4b+12b\leq-14-18\,and\,-14-14\leq-5b+12b\\16b\leq-32\,and\,-28\leq7b\\b\leq-\frac{32}{16}\,and\,-\frac{28}{7}\leq b\\b\leq-2\,and\,b\geq-4\\-4\leq b \leq-2
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3/4 yard long and 1/2 yard tall what is the area of the poster frame
zmey [24]
The area is 3/8 yd².

Area = length x width

Given:
length = 3/4 yard
width = 1/2 yard

Area = 3/4 yd * 1/2 yd
Area = 3*1/4*2
Area = 3/8 yd²

In multiplying fractions, multiply the numerators, then, multiply the denominators. lastly, simplify the fraction. 3/8 yd² is already in its simplest form.
3 0
3 years ago
Read 2 more answers
What's 2 ÷ 96 and does any one want my s n a p c h a t
oksano4ka [1.4K]
The answer is 47 no I don’t want thank you
8 0
3 years ago
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Evaluate 3/7r + 5/8s when r= 14 and s= 8
jasenka [17]

Answer:

11

Step-by-step explanation:

Step 1:

3/7r+5/8s

Step 2:

So u multiply 3/7 by 14

3/7 x 14= 42/7= 6

Step 2.5:

Now u multiply 5/8 by 8

5/8 x 8= 40/8= 5

Step 3:

<u><em>6+5=11</em></u>

6 0
3 years ago
Expand &amp; simplify:<br> (x - 1 )(x - 1)
andrey2020 [161]

Answer:

x^2 -2x+1

Step-by-step explanation:

(x - 1 )(x - 1)

FOIL

first: x*x = x^2

Outer: -1x

inner: -1x

Last: -1*-1 = 1

Add these together

x^2 -1x-1x+1

x^2 -2x+1

5 0
3 years ago
Read 2 more answers
4TH TIME ASKING THIS!!! Please help me! Someone pleaseeee. I need the correct answers. I don’t want to fail
Alexeev081 [22]

Answer:

The functions are inverses; f(g(x)) = x ⇒ answer D

h^{-1}(x)=\sqrt{\frac{x+1}{3}} ⇒ answer D

Step-by-step explanation:

* <em>Lets explain how to find the inverse of a function</em>

- Let f(x) = y

- Exchange x and y

- Solve to find the new y

- The new y = f^{-1}(x)

* <em>Lets use these steps to solve the problems</em>

∵ f(x)=\sqrt{x-3}

∵ f(x) = y

∴ y=\sqrt{x-3}

- Exchange x and y

∴ x=\sqrt{y-3}

- Square the two sides

∴ x² = y - 3

- Add 3 to both sides

∴ x² + 3 = y

- Change y by f^{-1}(x)

∴ f^{-1}(x)=x^{2}+3

∵ g(x) = x² + 3

∴ f^{-1}(x)=g(x)

∴ <u><em>The functions are inverses to each other</em></u>

* <em>Now lets find f(g(x))</em>

- To find f(g(x)) substitute x in f(x) by g(x)

∵ f(x)=\sqrt{x-3}

∵ g(x) = x² + 3

∴ f(g(x))=\sqrt{(x^{2}+3)-3}=\sqrt{x^{2}+3-3}=\sqrt{x^{2}}=x

∴ <u><em>f(g(x)) = x</em></u>

∴ The functions are inverses; f(g(x)) = x

* <em>Lets find the inverse of h(x)</em>

∵ h(x) = 3x² - 1 where x ≥ 0

- Let h(x) = y

∴ y = 3x² - 1

- Exchange x and y

∴ x = 3y² - 1

- Add 1 to both sides

∴ x + 1 = 3y²

- Divide both sides by 3

∴ \frac{x + 1}{3}=y^{2}

- Take √ for both sides

∴ ± \sqrt{\frac{x+1}{3}}=y

∵ x ≥ 0

∴ We will chose the positive value of the square root

∴ \sqrt{\frac{x+1}{3}}=y

- replace y by h^{-1}(x)

∴ h^{-1}(x)=\sqrt{\frac{x+1}{3}}

4 0
3 years ago
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