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fomenos
3 years ago
11

Problem page the length of a rectangle is 6 cm longer than its width. if the perimeter of the rectangle is 40 cm , find its area

.
Mathematics
1 answer:
steposvetlana [31]3 years ago
4 0
P = 2(L + W)
P = 40
L = W + 6

40 = 2(W + 6 + W)
40 = 2(2W + 6)
40 = 4W + 12
40 - 12 = 4W
28 = 4W
28/4 = W
7 = W....so the width is 7 cm

L = W + 6
L = 7 + 6
L = 13....and the length is 13 cm

the area is the length times the width
A = L * W
A = 13 * 7
A = 91 cm^2 <===
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2 years ago
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8 0
4 years ago
Please please help me
denis-greek [22]

Answer:

  151.4496 cm²

Step-by-step explanation:

The area of a trapezoid is found using the formula ...

  A = (1/2)(b1 +b2)h

where b1 and b2 are the lengths of the parallel bases and h is the distance between them. Fill in the numbers and do the arithmetic.

  A = (1/2)(22.2 cm + 8.52 cm)(9.86 cm) = 151.4496 cm²

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