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3 years ago

14

An ant has a length of approximately 7 × 10–3 meters and an anaconda has a length of approximately 6 x 100 meters. About how man

y times longer is the anaconda as compared to the ant?

1 answer:

Alexus [3.1K]3 years ago

3 0

Ant = .007
anaconda =6

anaconda is 857.142857 times longer

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A new online music service has a collection of 1,500 songs. It expects to triple the number of songs each year for the next few

Rzqust [24]

Answer: y = (3^(x-1))*1500

Step-by-step explanation:

We want the relationship

y = f(x)

where y is the number of songs, and x is the number of years.

We know that in the first year, x = 1, the site has 1,500 songs.

The next year, x = 2, the number of songs is tripled, then we will have:

1,500*3 = 4500 songs.

The next year, x = 3, we will have: 3*(3*1500) = (3^2)*1500.

when x = 4, the number is tripled again:

3*(3^2)*1500 = (3^3)*1500

We already can see the pattern, for the year x, the site will have:

y = (3^(x-1))*1500 songs.

This is the equation we are looking for.

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3 years ago

Line segment MN is graphed in the first and second quadrants of a coordinate plane. The segment is translated 2 units up, then r

Ksju [112]

Answer:

Step-by-step explanation:

Since the line segment is only being translated and reflected it would still maintain its length. This is pretty much the only characteristic that would remain the same as te original line segment. It would not maintain the same x-axis positions for both endpoints of the line segment. This is because when it is translated 2 units up it is only moving on the y-axis and not the x-axis. But when it is reflected over the y-axis the endpoints flip and become the opposite values.

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3 years ago

When finding the margin of error for the mean of a normally distributed population from a sample, what is the critical probabili

svlad2 [7]

Critical probability is the essentially cut-off value. The critical probability when the confidence level of 58% is 0.79.

<h3>What is the critical probability?</h3>

Critical probability is the essentially cut-off value that defines the region where the test statistic is unlikely to lie.

As it is given that the confidence level is 58%. therefore, in order to calculate the critical probability, we need to calculate the margin of error within a set of data, and it is given by the formula

$\rm Critical\ Probability, (P*) = 1-\dfrac{\alpha }{2}$

where the value of the α is expressed as,

$\alpha= 1 -\dfrac{\rm Confidence\ interval}{100}$

Now, as the confidence interval is given to us, therefore, the value of the alpha can be written as,

$\alpha= 1 -\dfrac{\rm 58\%}{100} = 0.42$

Further, the critical probability, assuming a confidence level of 58% is,

$\rm Critical\ Probability, (P*) = 1-\dfrac{\alpha }{2}\\\\\rm Critical\ Probability, (P*) = 1-\dfrac{0.42}{2} = 0.79$

Hence, the critical probability is 0.79.

Learn more about Critical Probability:

brainly.com/question/5625386

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2 years ago

Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)

andrew11 [14]

Use the distance formula.

$\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}$

Points S and W.
$\sqrt{(3)^2 + (2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points S and T
$\sqrt{(3 - 0)^2 + (-2 - 0)^2}$

$\sqrt{(3)^2 + (-2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points T and U
$\sqrt{(3 - 2)^2 + (-2 + 5)^2}$

$\sqrt{(1)^2 + (3)^2}$

$\sqrt{1+9}$

$\sqrt{10}$

~3.1

Points U and V
$\sqrt{(2+2)^2 + (-5 + 5)^2}$

$\sqrt{(4)^2 + (0)^2}$

$\sqrt{16}$

~4

Points V and W
$\sqrt{(-2+3)^2 + (-5 + 2)^2}$

$\sqrt{(1)^2 + (-3)^2}$

$\sqrt{2+9}$

$\sqrt{11}$

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17

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3 years ago

If x > 0, which of the following is closest to the value of x that makes the equation below true? ( SHOW WORK )

Semenov [28]

Answer:am working on this to study guide

Step-by-step explanation:

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3 years ago