1/6x =12
1x/6=12
—-
1x/6=12
x/6 =12
—-
x/6=12
6•x/6=6 • 12
——
x=72
C 1.5 , I am almost positive.
a) C(0.5) = 39, C(2) = 39, C(4) = 69
b) Answers in part (a) represents the values of C at x = x₀
c) C(x) is continuous at x = 2
C (x) = 39 for 0 ⩽ x ⩽ 2
Since x = 0.5 is in the range 0 ⩽ x ⩽ 2:
C(0.5) = 39
Since x = 2 is in the range 0 ⩽ x ⩽ 2
C(2) = 39
Since x = 4 is in the range x > 2
C(4) = 39 + 15(x - 2)
C(4) = 39 + 15 (4 - 2)
C(4) = 39 + 15(2)
C(4) = 39 + 30
C(4) = 69
b) The answers in part A represents C(x). That is, the values of C at x = x₀
c) Is C(x) continuous at x = 2
C(2) = 39

Since
, the function C(x) is continuous at x = 2
Learn more here: brainly.com/question/20710468
9/20
explanation:
7/10 - 1/4
14/20 - 5/20
14-5/20
9/20
10x10x10x10=10^4
10x10x10x10=10,000
6x10^5=6x100000
6x10^5=600000