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OlgaM077 [116]
3 years ago
14

Help!! due thursday tmrw help!

Mathematics
1 answer:
Flura [38]3 years ago
5 0

Answer:

12. w - 13 = 15 w = 28

13. g + 58 = 93 g = 35

14. n - 7 = 9   n = 16

Step-by-step explanation:

only 12-14

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Need help anyone asap xd?
Lemur [1.5K]

Answer:

B

Step-by-step explanation:

Let's start by converting each of these into decimal form.

\pi\approx 3.1416\\\sqrt{10}\approx 3.1623\\\dfrac{22}{7}\approx 3.1428

Therefore, the correct order is:

3.14, \pi, \dfrac{22}{7}, \sqrt{10}

or answer choice B. Hope this helps!

3 0
3 years ago
Read 2 more answers
Can someone help please...
Ivanshal [37]

Answer:

the answer is median (b)

8 0
3 years ago
John needs to divide the sample in half once the number of bacteria has reached 1000. How many hours after the initial time must
Reil [10]

Answer:

Option A

Step-by-step explanation:

The complete question is attached here

The rate of increase of bacterial population  be K

As we know

Y = Y_0 * e^{kT}

where Y is the final population. In this case it is 1000

K is the rate of increase of population i.e 3 times per hour

T is the time in hours

Y0 is the initial population = 5

Substituting the given values, we get -

1000 = 5 *e^{3*T}\\200 = e^{3*T}

Taking log on both sides, we get -

ln 200 = ln e^{3T}

2.718 * 2.301 = 3T

T = 2.084 hours

hence, option A is correct

8 0
3 years ago
What is the number 1,000 less than 28,648
Alexeev081 [22]

Answer:

27,648

Step-by-step explanation:

subtract 28,648 - 1,000

7 0
3 years ago
Read 2 more answers
A veterinarian collects data on the number of times race horses are raced during their careers. The veterinarian finds that the
SpyIntel [72]

Answer:

c. (12.12, 18.48)

Step-by-step explanation:

Hello!

The study variable is X: number of times a racehorse is raced during its career.

The average number is X[bar]= 15.3 and the standard deviation is S= 6.8 obtained from a sample of n=20 horses.

To estimate the population mean you need that the variable has a normal distribution, in this case, we have no information about its distribution so I'll assume that it has a normal distribution. With n=20 the most accurate statistic to use for the estimation is a Students-t for one sample, the formula for the interval is:

X[bar] ± t_{n-1;1-\alpha /2} * \frac{S}{\sqrt{20} }

t_{n-1;1-\alpha /2} = t_{19;0.975}= 2.093

[15.3 ± 2.093 * \frac{6.8}{\sqrt{20} }]

[12.12; 18.48]

Using a significance level of 95% you'd expect that the true average of times racehorses are raced during their career is included in the interval [12.12; 18.48].

I hope it helps!

8 0
3 years ago
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