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Tju [1.3M]
3 years ago
14

Two intersecting lines have ________ of point(s) in common.

Mathematics
1 answer:
vlada-n [284]3 years ago
3 0
It is b one have a good day
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What is the sum? 3 y / Y 2 + 7 y + 10 + 2 / y + 2​
kap26 [50]

Answer:

  5/(y+5)

Step-by-step explanation:

Perhaps you want the sum ...

  \dfrac{3y}{y^2+7y+10}+\dfrac{2}{y+2}\\\\=\dfrac{3y}{(y+2)(y+5)}+\dfrac{2(y+5)}{(y+2)(y+5)}=\dfrac{3y+2(y+5)}{(y+2)(y+5)}\\\\=\dfrac{5y+10}{(y+2)(y+5)}=\dfrac{5(y+2)}{(y+2)(y+5)}=\boxed{\dfrac{5}{y+5}}

_____

<em>Comment on rational expressions</em>

When writing ratios in plain text, it is imperative to put parentheses around numerators and denominators. (If the numerator is a product only, then parentheses are optional.)

Your expression might be properly written as ...

  3y/(y^2 +7y +10) +2/(y+2)

As you have written it, it simplifies to ...

  3(y/y)2 +7y +10 +2/y +2 = 3·2 +7y +2/y +12

  = 7y +2/y +18

Please note, too, the exponentiation symbol (^).

6 0
3 years ago
70000 is ten times as much as
svetlana [45]
70,000 is ten times as much as 7,000. This is because 7,000 times 10 equals 70,000. I got this answer by dividing 70,000 by 10.
6 0
3 years ago
Find A, B, and C <br> Help ASAP!<br> {10 points up}
Rama09 [41]

so we have a 60-30-90 triangle (top one)

so since we know 6 is x (the side on the right angle and 60 degrees)

b is 2x or 2(6) = 12

a is x√3 = 6√3


for C I need to use a 45 45 90 triangle

Since b is 12 and its x√2  to find x we should write it as

x√2 = 12

√2     √2  divide by √2

x = 12/√2  but we must rationalize the denominator

12/√2  times √2/√2  = 12√2/2 and that's c


6 0
3 years ago
Most of earths surface is mostly covered with
Svetach [21]
<span>C) salt water is the correct answer.</span>
7 0
4 years ago
the polynomial ky^3+3y^2-3 and 2y^3-5y+k when divided by (y-5) leave the same remainder in each case. Find the value of k.
marshall27 [118]

Answer:

k=\frac{153}{124}

Step-by-step explanation:

According to the Remainder Theorem; when P(y) is divided by y-a, the remainder is p(a).

The first polynomial is :

p(y)=ky^3+3y^2-3

When p(y) is divided by y-5, the remainder is

p(5)=k(5)^3+3(5)^2-3

p(5)=125k+75-3

p(5)=125k+72

When the second polynomial:

m(y)= 2y^3-5y+k is divided by y-5.

The remainder is;

m(5)= 2(5)^3-5(5)+k

m(5)= 225+k

The two remainders are equal;

\implies 125k+72=225+k

\implies 125k-k=225-72

\implies 124k=153

k=\frac{153}{124}

3 0
3 years ago
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