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3 years ago

Two intersecting lines have ________ of point(s) in common.

Mathematics

1 answer:

vlada-n [284]3 years ago

3 0

It is b one have a good day

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A spinner is labeled with the numbers 1,2,3,4,5,6,7,8, & 9.

Marat540 [252]

Answer:

Step-by-step explanation:

7 0

2 years ago

Simplify 19 - 1.67 + (-2.4)

-Dominant- [34]

19-1.67+(-2.4)
-19.73

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4 years ago

zack and are going to the fair. zack went on 3 rides and played 5 games and paid a total of $14. marissa paid $16 for 4 rides an

Rina8888 [55]

1 ride is $3 and 1 game is $1

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3 years ago

Pranay's school is selling tickets to the annual talent show. On the first day of ticket sales the

kozerog [31]

Answer:

Price of senior citizen ticket = $7

Price of student ticket = $5

Step-by-step explanation:

Let:

senior citizen ticket price = a
student ticket price = b

Equations formed :

9a + 10b = 113
2a + 10b = 64

Subtract : Equation 1 - Equation 2

9a + 10b - 2a - 10b = 113 - 64
7a = 49
a = 7

Finding b

2(7) + 10b = 64
10b = 50
b = 5

Solution

Price of senior citizen ticket = $7
Price of student ticket = $5

8 0

2 years ago

Read 2 more answers

Suppose that prices of recently sold homes in one neighborhood have a mean of $225,000 with a standard deviation of $6700. Using

elena55 [62]

Answer:

$211600 = 225000 -k*6700$

$k = \frac{225000-211600}{6700}= 2$

$238400 = 225000 +k*6700$

$k = \frac{238400-225000}{6700}= 2$

So then the % expected would be:

$1- \frac{1}{2^2}= 1- 0.25 =0.75$

So then the answer would be 75%

Step-by-step explanation:

For this case we have the following info given:

$\mu = 225000$ represent the true mean

$\sigma =6700$ represent the true deviation

And for this case we want to find the minimum percentage of sold homes between $211,600 and $238,400.

From the chebysev theorem we know that we have $1 -\frac{1}{k^2}$ % of values within $\mu \pm k\sigma$ if we use this formula and the limit given we have:

$211600 = 225000 -k*6700$

$k = \frac{225000-211600}{6700}= 2$

$238400 = 225000 +k*6700$

$k = \frac{238400-225000}{6700}= 2$

So then the % expected would be:

$1- \frac{1}{2^2}= 1- 0.25 =0.75$

So then the answer would be 75%

3 0

4 years ago