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Tju [1.3M]
3 years ago
14

Two intersecting lines have ________ of point(s) in common.

Mathematics
1 answer:
vlada-n [284]3 years ago
3 0
It is b one have a good day
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A spinner is labeled with the numbers 1,2,3,4,5,6,7,8, & 9.
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Answer:

Step-by-step explanation:

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7 0
2 years ago
Simplify 19 - 1.67 + (-2.4)
-Dominant- [34]
19-1.67+(-2.4)
-19.73
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4 years ago
zack and are going to the fair. zack went on 3 rides and played 5 games and paid a total of $14. marissa paid $16 for 4 rides an
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1 ride is $3 and 1 game is $1
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3 years ago
Pranay's school is selling tickets to the annual talent show. On the first day of ticket sales the
kozerog [31]

Answer:

Price of senior citizen ticket = $7

Price of student ticket = $5

Step-by-step explanation:

<u>Let</u>:

  • senior citizen ticket price = a
  • student ticket price = b

<u>Equations formed</u> :

  1. 9a + 10b = 113
  2. 2a + 10b = 64

<u>Subtract</u> : Equation 1 - Equation 2

  • 9a + 10b - 2a - 10b = 113 - 64
  • 7a = 49
  • a = 7

<u>Finding b</u>

  • 2(7) + 10b = 64
  • 10b = 50
  • b = 5

<u>Solution</u>

  • Price of senior citizen ticket = $7
  • Price of student ticket = $5
8 0
2 years ago
Read 2 more answers
Suppose that prices of recently sold homes in one neighborhood have a mean of $225,000 with a standard deviation of $6700. Using
elena55 [62]

Answer:

211600 = 225000 -k*6700

k = \frac{225000-211600}{6700}= 2

238400 = 225000 +k*6700

k = \frac{238400-225000}{6700}= 2

So then the % expected would be:

1- \frac{1}{2^2}= 1- 0.25 =0.75

So then the answer would be 75%

Step-by-step explanation:

For this case we have the following info given:

\mu = 225000 represent the true mean

\sigma =6700 represent the true deviation

And for this case we want to find the minimum percentage of sold homes between $211,600 and $238,400.

From the chebysev theorem we know that we have 1 -\frac{1}{k^2} % of values within \mu \pm k\sigma if we use this formula and the limit given we have:

211600 = 225000 -k*6700

k = \frac{225000-211600}{6700}= 2

238400 = 225000 +k*6700

k = \frac{238400-225000}{6700}= 2

So then the % expected would be:

1- \frac{1}{2^2}= 1- 0.25 =0.75

So then the answer would be 75%

3 0
4 years ago
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