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Annette [7]
3 years ago
5

Consider triangle GHJ.

Mathematics
2 answers:
gayaneshka [121]3 years ago
8 0
5 with square root 3 
bulgar [2K]3 years ago
5 0

we know that

<u>Applying the Pythagorean Theorem</u>

JG^{2} =HJ^{2}+HG^{2}

solve for HJ

HJ^{2}=JG^{2}-HG^{2}

in this problem we have

JG=10\ units\\ HG= 5\ units

Substitute the values in the formula above

HJ^{2}=10^{2}-5^{2}

HJ^{2}=100-25

HJ^{2}=75

HJ=\sqrt{75}=5\sqrt{3} \ units

therefore

<u>the answer is the option</u>

B. 5 sq. root 3 units

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telo118 [61]
<span>Using the points (2, 45) (4, 143) and (10, 869), we can plug them into the following system of 3 equations using the y = ax^2 + bx + c format:

45 = a(2)^2 + b(2) + c
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which simplifies to:

45 = 4a + 2b + c
143 = 16a + 4b + c
869 = 100a + 10b + c

Solving the system, we get a = 9, b = -5, and c = 19. Thus the equation is:

c(x) = 9x^2 - 5x + 19

If you have a TI graphing calculator, you can also enter the points by pressing Stat -> Edit and enter (2, 45) (4, 143) and (10, 869) into it. Go back and calculate the QuadReg of the points from the Calc tab and it will give you the same answer.

Now that we know the function that will produce the price of production for any number of calculators, plug in x = 7 and it will give you the price to produce 7 calculators.

c(x) = 9x^2 - 5x + 19
==> c(7) = 9(7)^2 - 5(7) + 19
==> c(7) = 441 - 35 + 19
==> c(7) = 425

Therefore, it costs $425 to produce 7 calculators.

Hope this helps.

</span>
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