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zepelin [54]
3 years ago
14

5. Mr. Martinez is getting a rug for his den and wants to make sure it will fit.He knows the area of the den is 547.35 square fe

et. He measured one wall and found it was 26.7 feet long. Mr. Martinez found a rug that measured 23.5 feet on all sides. Will this rug fit in Mr. Martinez's den? Explain.

Mathematics
1 answer:
evablogger [386]3 years ago
8 0
No.

If the Den is 547.35 Square feet, and one side length is 26.7, you divide the Area by one side length to get the other. 547.35/26.7= 20.5

20.5 is less than <span>23.5. Therefore the rug will not fit.</span>
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Find the rectangular coordinates of the point that has polar coordinates , 4, −3π/4
kirill115 [55]
Hello : 
 x= r cos<span>θ
 y= r sin</span><span>θ
r = 4   and  </span>θ =<span> −3π/4
cos( </span> −3π/4 )  = cos(  3π/4 ) = cos ( π - <span>π/4) = - cos (</span><span>π/4)= - </span><span>√2/2
</span>sin(  −3π/4 )  =  -  sin(  3π/4 ) = - sin ( π - π/4) = -sin (π/4)= - √2/2
x = - 2 √2
 y = - 2 √2

6 0
4 years ago
What is the domain of the function represented by the graph?
dezoksy [38]

Answer:  Choice C.  x \ge -3

============================================

Explanation:

The domain is the set of all allowed x inputs.

Here we see that x = -3 is the smallest x value possible as it is from the left-most point. The graph goes on forever to the right, so there is no largest x value. Effectively infinity is the largest x value even though infinity is not a number.

We can say the domain is -3 \le x < \infty which can be simplified to -3 \le x or x \ge -3

In short: x can be -3 or larger.

8 0
3 years ago
The National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time requir
Paha777 [63]

Answer:

95​% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

Step-by-step explanation:

We are given that the National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time required to earn their bachelor’s degrees. The mean was 5.15 years and the standard deviation was 1.68 years respectively.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                              P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean time = 5.15 years

            \sigma = sample standard deviation = 1.68 years

            n = sample of college graduates = 4400

            \mu = population mean time

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics although we are given sample standard deviation because the sample size is very large so at large sample values t distribution also follows normal.</em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5%

                                               level of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                                              = [ 5.15-1.96 \times {\frac{1.68}{\sqrt{4400} } } , 5.15+1.96 \times {\frac{1.68}{\sqrt{4400} } } ]

                                             = [5.10 , 5.20]

Therefore, 95​% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

8 0
3 years ago
Help me! Answer in pic not correct !
sladkih [1.3K]

Answer:

Q'=(4,1)\\R'=(6,-5)\\S'=(3,-4)\\T'=(1,-1)

Step-by-step explanation:

First we have to find the coordinates of the original ordered pairs then we will do the translation.

Q=(1,3)\\R=(3,-3)\\S=(0,-2)\\T=(-2,1)

Now we will add 3 to every x value and add a -2 to every y value.

Q=(1_{+3},3_{+(-2)})\\R=(3_{+3},-3_{+(-2)})\\S=(0_{+3},-2_{+(-2)})\\T=(-2_{+3},1_{+(-2)})

When you do that you will get the new prime points.

Q'=(4,1)\\R'=(6,-5)\\S'=(3,-4)\\T'=(1,-1)

8 0
3 years ago
Question 4 of 25
soldi70 [24.7K]

Answer:

D)graph c

Step-by-step explanation:

it's my opinion do not take it as important

7 0
2 years ago
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