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professor190 [17]
3 years ago
10

HT

Mathematics
2 answers:
mezya [45]3 years ago
6 0

Answer:

The answer is "I DON'T KNOW" Hope this helps!

Step-by-step explanation:

Sophie [7]3 years ago
4 0

Answer:

man what

Step-by-step explanation:

asallnlajsnksdvbusjc ma  sahd qfvsmcs,dvsf

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Malcolm has $638.54 in his checking account. He must maintain a $500 balance to avoid a fee. He wrote a check for $159.50 today.
gogolik [260]

Answer:

638.54-159.50+×> 500

Choose 3

Step-by-step explanation:

638.54-159.50=488.04

So the number added must make the value greater or equal to 500

7 0
3 years ago
You have $25,000 to invest. You can find an account (Acount A) that guarantees $925 per year. You also found a simple interest a
Sveta_85 [38]
Account A
A=p+i
A=25,000+(925×5)
A=29,625

Account B
A=p(1+rt)
A=25,000×(1+0.065×5)
A=33,125

How much more did the account B earn
33,125−29,625
=3,500

8 0
2 years ago
5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim
Ne4ueva [31]

Answer:

\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643

S_p=2.940

t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751

df=60+72-2=130

p_v =P(t_{130}

Assuming a significance level of \alpha=0.05 we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

n_1 =60 represent the sample size for people who used a self service

n_2 =72 represent the sample size for people who used a cashier

\bar X_1 =5.2 represent the sample mean for people who used a self service

\bar X_2 =6.1 represent the sample mean people who used a cashier

s_1=3.1 represent the sample standard deviation for people who used a self service

s_2=2.8 represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that  

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

And t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

System of hypothesis

Null hypothesis: \mu_1 \geq \mu_2

Alternative hypothesis: \mu_1 < \mu_2

This system is equivalent to:

Null hypothesis: \mu_1 - \mu_2 \geq 0

Alternative hypothesis: \mu_1 -\mu_2 < 0

We can find the pooled variance:

\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643

And the deviation would be just the square root of the variance:

S_p=2.940

The statistic is given by:

t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751

The degrees of freedom are given by:

df=60+72-2=130

And now we can calculate the p value with:

p_v =P(t_{130}

Assuming a significance level of \alpha=0.05 we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

5 0
3 years ago
A horseback riding trail is 1 mi 40.8 ft long. How long is the trail in yards, feet, and inches?
ch4aika [34]

Answer:  1773.6 yards   5320.8 feet  64324.8 inches

Step-by-step explanation:  

1 mile in yards = 1760                                                                                         40.8 feet in yards = 13.6      1760 + 13.6 =<u> 1773.6 yards </u>

1 mile in feet = 5280 + 40.8 = <u> 5320.8 feet </u>

1 mile in inches  = 63360

40.8 feet in inches = 964.8

63360 + 964.8 = <u>64324.8 inches </u>

<u>hope this helps :) </u>



6 0
3 years ago
Which of the following points does not lie on the graph of y=1/2x+3?
Gennadij [26K]

Answer:

B

Step-by-step explanation:

8 0
2 years ago
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