HT

Malcolm has $638.54 in his checking account. He must maintain a $500 balance to avoid a fee. He wrote a check for $159.50 today.

gogolik [260]

Answer:

638.54-159.50+×> 500

Choose 3

Step-by-step explanation:

638.54-159.50=488.04

So the number added must make the value greater or equal to 500

7 0

3 years ago

You have $25,000 to invest. You can find an account (Acount A) that guarantees $925 per year. You also found a simple interest a

Sveta_85 [38]

Account A
A=p+i
A=25,000+(925×5)
A=29,625

Account B
A=p(1+rt)
A=25,000×(1+0.065×5)
A=33,125

How much more did the account B earn
33,125−29,625
=3,500

8 0

2 years ago

5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim

Ne4ueva [31]

Answer:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

$S_p=2.940$

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

$df=60+72-2=130$

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

$n_1 =60$ represent the sample size for people who used a self service

$n_2 =72$ represent the sample size for people who used a cashier

$\bar X_1 =5.2$ represent the sample mean for people who used a self service

$\bar X_2 =6.1$ represent the sample mean people who used a cashier

$s_1=3.1$ represent the sample standard deviation for people who used a self service

$s_2=2.8$ represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

And t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

System of hypothesis

Null hypothesis: $\mu_1 \geq \mu_2$

Alternative hypothesis: $\mu_1 < \mu_2$

This system is equivalent to:

Null hypothesis: $\mu_1 - \mu_2 \geq 0$

Alternative hypothesis: $\mu_1 -\mu_2 < 0$

We can find the pooled variance:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

And the deviation would be just the square root of the variance:

$S_p=2.940$

The statistic is given by:

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

The degrees of freedom are given by:

$df=60+72-2=130$

And now we can calculate the p value with:

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

5 0

3 years ago

A horseback riding trail is 1 mi 40.8 ft long. How long is the trail in yards, feet, and inches?

ch4aika [34]

Answer: 1773.6 yards 5320.8 feet 64324.8 inches

Step-by-step explanation:

1 mile in yards = 1760 40.8 feet in yards = 13.6 1760 + 13.6 = 1773.6 yards

1 mile in feet = 5280 + 40.8 = 5320.8 feet

1 mile in inches = 63360

40.8 feet in inches = 964.8

63360 + 964.8 = 64324.8 inches

hope this helps :)

6 0

3 years ago

Which of the following points does not lie on the graph of y=1/2x+3?

Gennadij [26K]

Answer:

B

Step-by-step explanation:

8 0

2 years ago