Find the side length of a square with the given area. 121in(2 Exponent)

Please Help! In which of the following intervals does the trigonometric inequality sec(x)

timofeeve [1]

Step-by-step explanation:

sec(x) = 1/cos(x)

cot(x) = cos(x)/sin(x)

sec is smaller than cot, if cos is negative (making sec negative) and sin is negative (making cot positive).

and that is true for the third quadrant.

which is pi < x < 3×pi/2

so, the third answer is right.

3 0

2 years ago

I need help I'm in high school algebra 2 and I have a quiz that I need to pass I need someone to help me. Its about adding and s

Tatiana [17]

Answer:

do you have like a picture of the questions

Step-by-step explanation:

6 0

2 years ago

How to solve x+3y=3 and 2x-3y=-12

Sever21 [200]

Get x on one side then you can use substitution
So, change x+3y=3 to x= -3y+3
Then plug in x to other equation to find y
2(-3y +3)-3y=-12
-6y + 6 -3y = -12
-9y = -18
Divide both sides by negative nine to find y
y = 2
Then plug in to original equation to find x
x + 3(2) = 3
x + 6 = 3
x = -3
So, y = 2 and x = -3

3 0

3 years ago

Read 2 more answers

Choose 5 cards from a full deck of 52 cards with 13values (2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A) and 4 kinds(spade, diamond, h

Delvig [45]

Answer:

a) 182 possible ways.

b) 5148 possible ways.

c) 1378 possible ways.

d) 2899 possible ways.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question, we have that:

There are 52 total cards, of which:

13 are spades.

13 are diamonds.

13 are hearts.

13 are clubs.

(a)Two-pairs: Two pairs plus another card of a different value, for example:

2 pairs of 2 from sets os 13.

1 other card, from a set of 26(whichever two cards were not chosen above). So

$T = 2C_{13,2} + C_{26,1} = 2*\frac{13!}{2!11!} + \frac{26!}{1!25!} = 182$

So 182 possible ways.

(b)Flush: five cards of the same suit but different values, for example:

4 combinations of 5 from a set of 13(can be all spades, all diamonds, and hearts or all clubs). So

$T = 4*C_{13,5} = 4*\frac{13!}{5!8!} = 5148$

So 5148 possible ways.

(c)Full house: A three of a kind and a pair, for example:

4 combinations of 3 from a set of 13(three of a kind ,c an be all possible kinds).

3 combinations of 2 from a set of 13(the pair, cant be the kind chosen for the trio, so 3 combinations). So

$T = 4*C_{13,3} + 3*C_{13.2} = 4*\frac{13!}{3!10!} + 3*\frac{13!}{2!11!} = 1378$

So 1378 possible ways.

(d)Four of a kind: Four cards of the same value, for example:

4 combinations of 4 from a set of 13(four of a kind, can be all spades, all diamonds, and hearts or all clubs).

1 from the remaining 39(do not involve the kind chosen above). So

$T = 4*C_{13,4} + C_{39,1} = 4*\frac{13!}{4!9!} + \frac{39!}{1!38!} = 2899$

So 2899 possible ways.

4 0

3 years ago

Fifty people were surveyed about their favorite flavor of frozen yogurt. The results of the survey are displayed in the circle g

Ksju [112]

The answer is 2. This is because 2 = 4% of 50.

You can think of it like this:

4 is 4% of 100.

50 is half of 100.

Therefore, 4% of 50 is HALF of 4% of 100.

4 divided by 2 = 2

4 0

3 years ago