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Ugo [173]
3 years ago
14

Okay I need help: F(x)=x^2-5 find f(3)

Mathematics
2 answers:
MissTica3 years ago
5 0

Answer:

f(3)=4

Step-by-step explanation:

f(x)=x^2-5

f(3)=3^2-5

f(3)=3*3-5

f(3)=9-5

f(3)=4

Paladinen [302]3 years ago
4 0

f(x) = x^2 -5

Find f(3)

This means find x when it is 3 so just substitute 3 for x

f(3) = 3^2 -5

= 9 - 5

f(3) = 4

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The height of a golfball hit off a 128-foot hill is modeled by the function h(t) = −16t2 + 32t + 128, where h is height in feet
taurus [48]

The time taken for the golf ball to reach the ground is 1 s.

<h3>Motion of the golf ball</h3>

The path of motion of the golf ball can be described as parabolic because it is projectile.

When the golf ball reaches the ground, the final velocity will be zero.

Velocity of the golf ball is change in height with time.

v = dh/dt

h(t) = -16t² + 32t  + 128

dh/dt = -32t + 32

0 = -32t + 32

32t = 32

t = 1 s

Thus, the time taken for the golf ball to reach the ground is 1 s.

Learn more about time of  motion here: brainly.com/question/2364404

5 0
2 years ago
What is the radical form of each of the given expressions? Drag the answer into the box to match each expression.
postnew [5]

4 ^ (1/7 ) is the 7th root of 4 or the 3rd box

4 ^ (7/2) is 4 to the 7th power then the square root  or the 2nd box

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7 ^ (1/2) is the square root of 7 or the  6th box

4 0
3 years ago
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Julia is the president of the technology Club at school she has $568 to buy as many DVD players as she can for $75 each how many
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5 0
3 years ago
Is the difference of 1.48-0.25 less or greater than one
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4 years ago
Which step is the same in the construction of parallel lines and the construction of a perpendicular line through a point on the
madam [21]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

<em># Contracting parallel lines</em>

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2.<u> Place the pin of the compass at point C</u> and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

<em># Constructing a perpendicular line through a point on the line</em>

- Given line AB and point P lies on it

1. <u>Place your compass pin at P </u>and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3.<u> </u>Place the compass pin on point C<u> </u>and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

*<em> Lets find the same steps in the constructions</em>

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  <em><u>"Place the compass on a point on the original line"</u></em>

6 0
3 years ago
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