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Ksenya-84 [330]
3 years ago
11

Solve for x in the equation

Mathematics
1 answer:
Viktor [21]3 years ago
5 0

Answer:

{x}^{2}  + 2x + 1 = 17 \\  {x}^{2}  + 2x - 16 = 0 \\ x =  \frac{ - b± \sqrt{ {b}^{2}  - 4ac} }{2a}  \\ x =  \frac{ - 2± \sqrt{68} }{2}  \\ x =  \frac{ - 2±2 \sqrt{17} }{2 }  \\ x =  - 1± \sqrt{17}

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