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Ksenya-84 [330]
3 years ago
11

Solve for x in the equation

Mathematics
1 answer:
Viktor [21]3 years ago
5 0

Answer:

{x}^{2}  + 2x + 1 = 17 \\  {x}^{2}  + 2x - 16 = 0 \\ x =  \frac{ - b± \sqrt{ {b}^{2}  - 4ac} }{2a}  \\ x =  \frac{ - 2± \sqrt{68} }{2}  \\ x =  \frac{ - 2±2 \sqrt{17} }{2 }  \\ x =  - 1± \sqrt{17}

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Answer:

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Step-by-step explanation:

these are just translations up and to the right.

since the f(x)=x^2

the transformations would be

1. g(x)=x^2+5

2.g(x)=(x-3)^2 = x^2-6x+9

4 0
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Write 7x10x10x10x10 with an exponent
polet [3.4K]

Answer:

7x10^4

Step-by-step explanation:

Please add the thanks and rate me please

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Ilia_Sergeevich [38]

By the quadratic formula, the <em>solution</em> set of the <em>quadratic</em> equation is formed by two <em>real</em> roots: x₁ = 0 and x₂ = - 12.

<h3>How to find the solution of quadratic equation</h3>

Herein we have a <em>quadratic</em> equation of the form a · m² + b · m + c = 0, whose solution set can be determined by the <em>quadratic</em> formula:

x = - [b / (2 · a)] ± [1 / (2 · a)] · √(b² - 4 · a · c)      (1)

If we know that a = - 1, b = 12 and c = 0, then the solution set of the quadratic equation is:

x = - [12 / [2 · (- 1)]] ± [1 / [2 · (- 1)]] · √[12² - 4 · (- 1) · 0]

x = - 6 ± (1 / 2) · 12

x = - 6 ± 6

Then, by the quadratic formula, the <em>solution</em> set of the <em>quadratic</em> equation is formed by two <em>real</em> roots: x₁ = 0 and x₂ = - 12.

To learn more on quadratic equations: brainly.com/question/1863222

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1.15(300)=345 miles per hour
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8 0
3 years ago
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Answer:

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Step-by-step explanation:

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