Answer:
16
Step-by-step explanation:
7 + 54/3*2
simplify the fraction
=7 + 54/6
=7 + 9
= 16
Let a,b,c,d and e are five numbers
mean = (a +b+ c+ d+e)/5 = 30
⇒ (a +b+ c+ d+e) = 150_______(1)
now, Let the number excluded be a
then, new mean = (b+ c+ d+e)/4 = 28
⇒ (b+ c+ d+e)= 112
putting this value in (1),
⇒a + 112 = 150
⇒a = 150 -112 = 38
excluded number = 38
Answer:
The expected value of the game to the player is -$0.2105 and the expected loss if played the game 1000 times is -$210.5.
Step-by-step explanation:
Consider the provided information.
It is given that if ball lands on 29 players will get $140 otherwise casino will takes $4.
The probability of winning is 1/38. So, the probability of loss is 37/38.
Now, find the expected value of the game to the player as shown:



Hence, the expected value of the game to the player is -$0.2105.
Now find the expect to loss if played the game 1000 times.
1000×(-$0.2105)=-$210.5
Therefore, the expected loss if played the game 1000 times is -$210.5.
Answer:
74.958
Step-by-step explanation:
Because 57.66 added 30 percent is equal to 74.958
I believe it is GCF because 9v^3 can be factored out of the expression, becoming:
9v^3 (4 - 3v^2)
9v^3 (-3v^2 + 4)
The quadratic in parentheses can be solved, but with the quadratic equation or by graphing.