Answer:
10%
Explanation:
The distance between the given two loci is 20 mu. This means that the recombination frequency between these two loci is 20% and the heterozygote will form 20% recombinant gametes and rest 80% parental type gametes. Therefore, the heterozygous woman AB/ab will form a total of 20% recombinant gametes. The proportion of each recombinant gamete will be 20/2= 10%.
Gametes formed by the woman= 10% Ab, 10% aB, 40% AB, and 40% ab
Gametes formed by the man= All ab (since the man is homozygous for both loci).
Therefore, proportion of Ab/ab genotype= 10% Ab (female gamete) x ab (male gamete)= 10% Ab/ab
Answer:
The systolic pressure is 120, and the diastolic p
ressure is 80.
The intensity of a stimulus, such as the intensity of noise that a person experiences, can be communicated through the number of neurons that fire action.
A stimulus is a change detected by the neurons in a body for which a response is produced. The sensory nerves sense a stimulus and send signals to the brain. The brain interprets this message and sends a response action signal through the motor neurons.
The intensity of a stimulus is detected by the impulse of action potential carried by the sensory neurons. The number of sensory neurons will increase if an intense stimulus, which will lead to the generation of an increased action potential. The brain will determine the intensity of the increased action potential and send a response action from the motor neurons to act accordingly.
To learn more about neurons, click here:
brainly.com/question/11538106
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