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3 years ago

I really need help plz help if you help I will help you to

Mathematics

1 answer:

lidiya [134]3 years ago

5 0

2. 3/4
3. equal
4. not equal
5. not equal
6. equal
8. 8/12 2/3
9. draw two squares and divide them both into 3 sections. In the first square color in one section and in the second square color in two sections.

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LOOK AT PIC! HELP! :)

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33 Million dollars have been made.

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3 years ago

Review the diagram of a locket in the shape of an ellipse.

Helen [10]

Answer:

Step-by-step explanation:

If you graph y^2/361 + x^2/169=1 you will get the same graph depicted in the equation.

8 0

3 years ago

Read 2 more answers

Help? y - intercepts <br> What is the y-intercept of the equation 2x + 3y = 12?

Nookie1986 [14]

Answer:

2x + 3y = 12 Is the standard form for linear equations. To determine the slope, solve the equation for y in order to convert to the slope - intercept from7 y = mx + b where is m the slop and b is the y - intercept.

2x + 3y = 12

subtract 2x from both sides.

3y = -2x + 12

Divide both sides by 3.

y= - 2/3 x + 12/3 =

y= - 2/3x + 4

The slope is - 2/3

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2 years ago

Marc is building a rectangular wooden frame for his canvas. If the canvas is 7 feet long by 5 feet wide, what is the perimeter o

Assoli18 [71]

Answer:

24 feet

Step-by-step explanation:

Use the perimeter formula, P = 2l + 2w, where l is the length and w is the width.

Plug in the values, and solve:

P = 2l + 2w

P = 2(7) + 2(5)

P = 14 + 10

P = 24

So, the perimeter of the canvas is 24 feet

8 0

3 years ago

Consider the following data set. The data were actually collected in pairs, and each row represents a pair.

Anna11 [10]

Answer:

Step-by-step explanation:

Hello!

Using the data sets you have to analyze them as if they are two independent samples.

The hypotheses are:

H₀: μ₁=μ₂

H₁: μ₁≠μ₂

α: 0.05

Assuming that both data sets are from a normal distribution and both population variances, although unknown, are equal, the statistic to use is:

$t=\frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}$

$Sa^2= \frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2}$

$Sa^2= \frac{9*5.38+9*3.65}{10+10-2} =4.51$

Sa= 2.12

$t_{H_0}= \frac{(49.69-50.52)-0}{2.12*\sqrt{\frac{1}{10} +\frac{1}{10} } } = -0.875$

The p-value for the two-tailed test is:

P( $t_{18}$ ≤-0.875) + P( $t_{18}$ ≥0.875)= P( $t_{18}$ ≤-0.875) + (1 - P( $t_{18}$ ≤0.875))= 0.1965 + ( 1 - 0.8035)= 0.393

Since there is no significant level I determined it at 5%, comparing it to the p-value, the hypothesis test is not significant. Meaning that the difference between the population means of both groups is equal to zero.

Considering the given data as a paired sample, you have to determine the variable difference to conduct the test:

Xd: the difference between X₁ and X₂

Before the sample mean and sample standard deviation you have to calculate the difference between the observations of group 1 and group 2. (2nd attachment)

Mean X[bar]d= -0.83

Standard deviation Sd= 1.28

The hypotheses for the paired sample test are:

H₀: μd=0

H₁: μd≠0

α: 0.05

$t= \frac{X[bar]d-Mud}{\frac{Sd}{\sqrt{n} } } ~~t_{n-1}$

$t_{H_0}= \frac{-0.83-0}{\frac{1.28}{ \sqrt{10} }} = -2.05$

The p-value for the two-tailed test is:

P( $t_{9}$ ≤-2.05) + P( $t_{9}$ ≥2.05)= P( $t_{9}$ ≤-2.05) + (1 - P( $t_{9}$ ≤2.05))= 0.0353 + (1 - 0.9647)= 0.0706

Comparing the p-value with the significance level, the hypothesis test is not significant. Meaning that the population mean of the difference between group 1 and group 2 is equal to cero. There is no difference between the two groups.

The value of the statistic in "a" is greater than the value of the statistic obtained in "b". Since there are two samples used an "a" the degrees of freedom of the test are the double as the ones used in "b". The p-value obtained in "b" is around half of the p-value of "a".

The main difference is that in "a" you compared two different samples but in "b" you compared two dependent samples when analyzing paired data the "effect of the individual" is removed from the equation.

I hope this helps!

3 0

3 years ago