Answer:
probability that Shaun loses both games
Step-by-step explanation:
Games are independent, so we find each separate probability, and multiply them.
In a chess club the probability that Shaun will beat Mike is 3/8.
So 
probability that Shaun loses.
The probability that Shaun will beat Tim is 5/7 .
So 
probability that Shaun loses.
What is the probability that Shaun loses both games?
This is:
probability that Shaun loses both games
Answer:
4 people voted for hot dogs
Step-by-step explanation:
20-6-10=4
Answer:
Step-by-step explanation:
slope = -6
y-intercept=0
Answer:
3 days: 8 heads.
10 days: 1024 heads.
Step-by-step explanation:
If each time the hero cuts off all the heads, then the amount doubles each time. This can also be represented using powers of 2, with 2^n, where n is the number of days.
2^1 = 2, so two heads the first time he cuts it.
2^2 = 4, so four heads the second time he cuts it.
With three, 2^3 is 8 so there are 8 heads.
With ten, 2^10 is 1024 so there are 1024 heads.
