Question

write an equation with the solution x=20 the equation should have the variable on both sides a fractional coefficient on the left side and a fraction anywhere on the right side

Answer 1

Consider the equation

$\dfrac{1}{4}x-5=\dfrac{x-20}{3}$.

It is easy to see that x=20 is a solution of this equation, because when x=20:

$\dfrac{1}{4}x-5=\dfrac{1}{4}\cdot 20-5=5-5=0$,

$\dfrac{x-20}{3}=\dfrac{20-20}{3}=\dfrac{0}{3}=0$.

Also this equation have:

1. the variable on both sides;

2. a fractional coefficient on the left side;

3. a fraction on the right side.

Answer 2

Answer
24 1/2+3/4 x=2x-1/2

Explanation
A coefficient of x on the left hand side is 2/3. On the right hand side we have ½ as the fraction as required by the question.
The variable term x.
When we solve the equation above we get 20. The process is as shown,

24 1/2+3/4 x=2x-1/2
24 1/2+1/2=2x-3/4 x
25=1 1/4 x
25=5/4 x
x=25×4/5
x=20