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11Alexandr11 [23.1K]
3 years ago
5

A person who is 6 feet tall is standing 120 feet from the base of a tree, and the tree casts a 130 foot shadow. The person's sha

dow is 10 feet in length. What is the height of the tree?
Mathematics
1 answer:
g100num [7]3 years ago
6 0

Answer:

the tree is 65 feet high.

Step-by-step explanation:

let 'x' be the height of the tree

draw the tree, the person and the shadows - notice the similar triangles

the following proportion counts

x : 5 = 130 : 10

x = (5*130)/10

x = 65 feet

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4000 is 1/10 as much as what number
crimeas [40]
40,000

All you do is multiply 4,000 by 10 to find out what 10 times of your number is, if 4,000 is only 1/10 of it.
6 0
3 years ago
23, 24 And 25 please. Thank you!
Vesna [10]

Step-by-step explanation:

23. area of rect,r = 11 x 3.5 = 38.5cmsq

area of tri, t = 6 x3.5/2 = 10.5 cmsq

area of shaded region, sr = r-t

=> sr = 38.5- 10.5 = 28.5cmsq

24. area of square, s = 10x10 = 100mmsq

area of circle, c = pi x 5^2 = 78.5mmsq

area of shaded region, sr = s - c

=> sr = 100- 78.5 = 22.5mmsq

25. area of circle, c = pi x 6^2 = 113.04insq

area of tri, t = 6x12/2 = 36insq

area of shaded region, sr = c - t

=> sr = 113.04 - 36 = 77.04insq

3 0
3 years ago
Can anyone please help me with this?
Blizzard [7]

Answer:

8

Step-by-step explanation:

2/3·12=24/3=8

4 0
3 years ago
What is the period of the function f(x) shown in the graph?<br><br> Enter your answer in the box.
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6 0
2 years ago
AB is tangent to O. If AO = 32 and BC = 98, what is AB? my guess is 130? please help!
Juli2301 [7.4K]
    
CO = AO  = 32    (Are rays.)
BO = BC + CO = 98 + 32 = 130
AB ⊥ BO
⇒  ΔAOB   is a rectangular triangle.
We use Pitagora's theorem.


\displaystyle\\&#10;AB =  \sqrt{BO^2 - AO^2}  = \sqrt{130^2 -32^2}=\\\\&#10;= \sqrt{16900 -1024}= \sqrt{15876}= \boxed{126 }



7 0
4 years ago
Read 2 more answers
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