Answer:
yes
Step-by-step explanation:
x+1 and y+1 it is consistent the equation looks like 1(x)+ 8
Let any integer be represented by x.
Then, the consecutive integer (the number that follows) should be x+1.
The statement wants us to prove;
(x+1)²-x²=x+(x+1) <-- solve left hand side
x²+x+x+1²-x²
2x+1 (solution for left hand side)
Now solve for right hand side.
x+(x+1)= 2x+1
As noticed, the LHS=RHS (left hand side= right hand side), therefore, the difference of squared consecutive numbers subtracted is equal to the sum of the two integers.
Hope I helped :)
1.an = 3n - 1 2. an = 2(2n - 3) 3.an = 4^n 4.an = (2/3)^n 5. an = (-1)^n(n + 5) 6. an = (-1)^n + 1(n + 6) 7. an= n+3/2n-1 8. a1 = -5 and an = an-1 - 3 for n ≥ 2 9. a1 = -6 and an = -2an-1 for n ≥ 2 10.a1 = 4 and an = 3an-1 + 2 for n ≥ 2 11. Find a8 when a1...
It is not fair to do it like that.
Step-by-step explanation:
A pair of 6 sided dice is more likely to roll a bigger number than a smaller one.