Z/3 - 4(z-1) = 5(z-2)+1 What is the value of z?

Mathematics

1 answer:

Vadim26 [7]3 years ago

4 0

Answer: $\frac{3}{2}$

Step-by-step explanation:

First, we need to open the brackets on either side of the equation.

$\frac{z}3}$ - 4z+4 = 5z-10+1

After opening the brackets, we need to separate the variables from the constants.

$\frac{z}{3}$ -4z-5z = -10+1-4

Then we need to convert the variable fraction into a normal variable by multiplying the variable fraction and also all other terms in the equation.

3( $\frac{z}{3}$ ) 3(-4z) 3(-5z) = 3(-10) + 3(1) + 3(-4)

z -12z -15z = -30+3-12

Now, we can simplify the equation !

-26z = -39

z = -39÷-26

= $\frac{3}{2}$

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