2 over 8 divided by 1 over 2 =

1 answer:

7 0

Answer: 1 over 2 (1/2)

Simplify 2 over 8 to get 1 over 4. Now you have 1 over 4 divided by 1 over 2. Whenever you divide with fractions you flip the fraction and multiply . So it becomes 1 over 4 multiplied by 2 over 1.

2/8 (divided by) 1/2
1/4 (divided by) 1/2
1/4 x 2/1
= 1/2

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We can use the Сosine formula to solve this problem.
First we must find the third side (АС) of the triangle:

$AC^2=AB^2+BC^2-2*AB*BC*cos82^o \\ AC^2=8^2+11^2-2*8*11*0.1392 \\ AC^2=64+121-24.4992= 160.508 \\ AC= \sqrt{160.508} \approx 12.67 \ cm$

The smallest angle of the triangle lies opposite the smallest side, so we need to find m∠C.

$cosC= \frac{AC^2+BC^2-AB^2}{2*AC*BC} \\ \\ cosC= \frac{12.67^2+11^2-8^2}{2*12.67*11}= \frac{160.53+121-64}{278.74} = \frac{217.53}{278.74} \approx 0.7804$

Now we can use Bradis's Table (I don't know the name in English, maybe Trigonometric Table?) to find m∠C:

m∠С = 38°42' = 38.7°

Answer: 38.7°

I hope this helps