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8_murik_8 [283]
3 years ago
8

ONE, MANY, OR NO SOLUTION1. 4x + 13 = 3x + 15​

Mathematics
1 answer:
Svetllana [295]3 years ago
5 0

Answer:

one solution

Step-by-step explanation:

4x + 13 = 3x + 15

subtract 3x from both sides:

x + 13 = 15

subtract 13 from both sides:

x = 2

one solution

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\frac{1}{3}

Step-by-step explanation:

2 = 2 × 1

6 = 2 × 3

GCF = 2

\frac{2 /2 }{6/2} =\frac{1}{3}

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(a) What is wrong with the following equation? x2 + x − 42 x − 6 = x + 7 (x − 6)(x + 7) ≠ x2 + x − 42 The left-hand side is not
jeka94

Answer:

Attached please find answer

Step-by-step explanation:

= (x² + x - 42) / (x - 6)

= [x² + (7x - 6x) - 42] / (x - 6)

= [x² + 7x - 6x - 42] / (x - 6)

= [(x² + 7x) - (6x + 42)] / (x - 6)

= [x(x + 7) - 6(x + 7)] / (x - 6)

= [(x + 7)(x - 6)] / (x - 6)

= x + 7 → when x approches 6

= 6 + 7

= 13

Other method:

Lim   (x² + x - 42) / (x - 6)

x→ 6

When x → 6, there is an indeterminate expression because: 6 - 6 = 0

Do you know the l'Hôpital's rule, when x → a:

Lim [ f(x) / g(x) ] = Lim [ f'(x) / g'(x) ]

f(x) = x² + x - 42

f'(x) = 2x + 1

g(x) = x - 6

g'(x) = 1

= f'(x) / g'(x)

= (2x + 1)/1

= 2x + 1 → when x approches 6

= 12 + 1

= 13

3 0
3 years ago
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