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2 years ago

The first four multiples of 7 are 7, 14 21, and 28. Use this example to help you as you answer the questions below.

Mathematics

1 answer:

Pachacha [2.7K]2 years ago

6 0

Answer:

For A. it would be 9, 18, 27, 36, 45, 54

For B. it would be 12, 24, 36, 48, 60, 72

For C. it would be 36

For D. it would be 3

Step-by-step explanation:

Hope this helps

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(08.01) The graph shows two lines, Q and S. A coordinate plane is shown with two lines graphed. Line Q has a slope of one half a

ki77a [65]

Answer:

There are no solutions for the pair of equations.

The lines are parallel to each other

Step-by-step explanation:

Line Q has a slope of 1/2 and crosses the y axis at 3.

This mean at x=0, y=3

Using the equation of a straight line expression to find the slope

y=mx +c where m is slope and c in the y intercept you can write the equation for Line Q as;

$y=mx+c\\\\y=\frac{1}{2} x+c\\\\3=\frac{1}{2} *0+c\\\\3=c\\\\y=\frac{1}{2} x+3$

For the Line S , slope is 1/2 and the line crosses the y axis at -2 , which represents the c in the equation y=mx +c

The equation for S will be

$y=\frac{1}{2} x-2$

Using the graphing tool to plot the two equations for line Q and line S we notice that the lines are parallel .For solutions, they have to intersect.

8 0

3 years ago

Read 2 more answers

Consider the differential equation:

Wewaii [24]

(a) Take the Laplace transform of both sides:

$2y''(t)+ty'(t)-2y(t)=14$

$\implies 2(s^2Y(s)-sy(0)-y'(0))-(Y(s)+sY'(s))-2Y(s)=\dfrac{14}s$

where the transform of $ty'(t)$ comes from

$L[ty'(t)]=-(L[y'(t)])'=-(sY(s)-y(0))'=-Y(s)-sY'(s)$

This yields the linear ODE,

$-sY'(s)+(2s^2-3)Y(s)=\dfrac{14}s$

Divides both sides by $-s$ :

$Y'(s)+\dfrac{3-2s^2}sY(s)=-\dfrac{14}{s^2}$

Find the integrating factor:

$\displaystyle\int\frac{3-2s^2}s\,\mathrm ds=3\ln|s|-s^2+C$

Multiply both sides of the ODE by $e^{3\ln|s|-s^2}=s^3e^{-s^2}$ :

$s^3e^{-s^2}Y'(s)+(3s^2-2s^4)e^{-s^2}Y(s)=-14se^{-s^2}$

The left side condenses into the derivative of a product:

$\left(s^3e^{-s^2}Y(s)\right)'=-14se^{-s^2}$

Integrate both sides and solve for $Y(s)$ :

$s^3e^{-s^2}Y(s)=7e^{-s^2}+C$

$Y(s)=\dfrac{7+Ce^{s^2}}{s^3}$

(b) Taking the inverse transform of both sides gives

$y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]$

I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that $\frac{7t^2}2$ is one solution to the original ODE.

$y(t)=\dfrac{7t^2}2\implies y'(t)=7t\implies y''(t)=7$

Substitute these into the ODE to see everything checks out:

$2\cdot7+t\cdot7t-2\cdot\dfrac{7t^2}2=14$

5 0

3 years ago

Why is the vector ???????? = 〈0,0〉 called the zero vector? Describe its geometric effect when added to another vector

Mamont248 [21]

Step-by-step explanation:

A vector is defined as an object which has got some value or magnitude and has a direction as well.

The vector =(0,0) is called the zero vector because it has zero length and no direction at all. The zero vector has an undefined direction.

The zero vector behaves same as the number zero and when added to any vector say "a", we get the answer as vector "a" which remains unchanged.

6 0

3 years ago

Hii please help asap ill give brainliest thanks

lesya692 [45]

The teachings of buddha is the answer :-)

3 0

3 years ago

Read 2 more answers

PLS HELP ASAP I NEED THIS

crimeas [40]

Answer:

Step-by-step explanation:

Firstly let's see definition of Rational numbers ,

Rational numbers :-

The number in the form of p/ q where p and q are integers and q is not equal to zero is called a Rational number .

From the options , look at option D ,its

→ √400

→ √{20²}

→ 20

<h3>Hence option D is correct.</h3>

6 0

3 years ago