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LuckyWell [14K]
3 years ago
13

What are the prime factors of 28?

Mathematics
2 answers:
koban [17]3 years ago
5 0

Answer:

2 and 7 are the prime numbers.

Step-by-step explanation:

Tju [1.3M]3 years ago
5 0

Answer:

28=2 x 2 x7

Step-by-step explanation:

draw a prime factor tree

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Plz help. Simplifying simplify the answers
galben [10]
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Benny earns $12.00 per hour as a lifeguard. He earns a bonus of $75.00 for taking a training course. Which graph best represents
Scorpion4ik [409]

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C.

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2 years ago
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The volume of a cylindrical soup can is represented by the expression πr3 + 7πr2, where r is the radius of the cylinder. Which s
Ganezh [65]

Answer:

Step-by-step explanation:

Given the volume of the cylindrical soup expressed as V = πr³+ 7πr²

From V = πr³ + 7πr²;

factor out the common variable

V = πr³ + 7πr²

V = πr²(r+7) ... 1

The original volume of a cylinder V =  πr²h .... 2 where;

r is the radius of the cylinder

h is the height of the cylinder

Equating equation 1 and 2, we will have;

πr²(r+7)  =  πr²h

Divide both sides by  πr²

πr²(r+7)/ πr² = πr²h/ πr²

r+7 = h

h = r+7

<em>Hence the factor in the context given is equivalent to the height of the cylinder written as a function of its radius r</em>.<em> The statement means that the height of the cylindrical soup is 7 more than its radius.</em>

<em></em>

5 0
3 years ago
Explain how patterns are used in mathematics
jeka94

Answer:

shapes

Step-by-step explanation:

The patterns are shapes

8 0
3 years ago
Find the EXACT value of sin(A−B) if cos A = 3/5 where A is in Quadrant IV and cos B = 12/13 where B is in Quadrant IV. Assume al
MissTica

\bf \textit{Sum and Difference Identities} \\\\ sin(\alpha - \beta)=sin(\alpha)cos(\beta)- cos(\alpha)sin(\beta)

well, for both angles A and B we're on the IV Quadrant, meaning, the sine is negative, the cosine is positive, likewise, the opposite side is negative and the adjacent side for the angle is positive.

\bf cos(A)=\cfrac{\stackrel{adjacent}{3}}{\underset{hypotenuse}{5}}\qquad \qquad \stackrel{\textit{getting the opposite side}}{b=\pm\sqrt{5^2-3^2}}\implies b = \pm 4 \\\\\\ \stackrel{IV~Quadrant}{b = -4}\qquad \qquad sin(A)=\cfrac{\stackrel{opposite}{-4}}{\underset{hypotenuse}{5}} \\\\[-0.35em] ~\dotfill\\\\ cos(B)=\cfrac{\stackrel{adjacent}{12}}{\underset{hypotenuse}{13}}\qquad \qquad \stackrel{\textit{getting the opposite side}}{b=\pm\sqrt{13^2-12^2}}\implies b = \pm 5

\bf \stackrel{IV~Quadrant}{b = -5}\qquad \qquad sin(B)=\cfrac{\stackrel{opposite}{-5}}{\underset{hypotenuse}{13}} \\\\[-0.35em] ~\dotfill\\\\ sin(A-B)=\cfrac{-4}{5}\cdot \cfrac{12}{13}-\left( \cfrac{3}{5}\cdot \cfrac{-5}{13} \right)\implies sin(A-B)=\cfrac{-48}{65} - \left( \cfrac{-15}{65} \right) \\\\\\ sin(A-B)=\cfrac{-48}{65} + \cfrac{15}{65}\implies sin(A-B)=\cfrac{-33}{65}

4 0
2 years ago
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