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Schach [20]
1 year ago
11

What are the zeros of g(x)= x³ + 6x² - 9x-54?

Mathematics
1 answer:
Veseljchak [2.6K]1 year ago
3 0

Answer:

3,-3

Step-by-step explanation:

g(3)= (3)³+6(3)²-9(3)-54

= 27+54-27-54

=81-81

= 0

g(-3) = (-3)³+6(-3)²-9(-3)-54

= -27+54+27-54

= 27-27

= 0

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Charra [1.4K]

Answer:

b. 0.50x+15=25

so the answer is 20

7 0
2 years ago
You are to manufacture a rectangular box with 3 dimensions x, y and z, and volume v=8000. Find the dimensions which minimize the
Inga [223]

Answer:

20 by 20 by 20

Step-by-step explanation:

Let the total surface of the rectangular box be expressed as S = 2xy + 2yz + 2xz

x is the length of the box

y is the width and

z is the height of the box.

S = 2xy + 2yz + 2xz ... 1

Given the volume V = xyz = 8000 ... 2

From equation 2;

z = 8000/xy

Substituting into equation 1;

S = 2xy + 2y(8000/xy)+ 2x(8000/xy)

S = 2xy+16000/x+16000/y

Differentiating the resulting equation with respect to x and y will give;

dS/dx = 2y + (-16000x⁻²)

dS/dx = 2y - 16000/x²

Similarly,

dS/dy = 2x  + (-160000y⁻²)

dS/dy = 2x - 16000/y²

Note that at the turning point, ds/dx = 0 and ds/dy = 0, hence;

2y - 16000/x² = 0 and 2x - 16000/y² = 0

2y = 16000/x² and 2x = 16000/y²

2y = 16000/(8000/y²)²

2y = 16000×y⁴/64,000,000

2y = y⁴/4000

y³ = 8000

y =³√8000

y = 20

Given 2x = 16000/y²

2x = 16000/20²

2x = 16000/400

2x = 40

x = 20

Since Volume of the box is V = xyz

8000 = 20(20)z

8000 = 400z

z = 8000/400

z = 20

Hence, the dimensions which minimize the surface area of this box is 20 by 20 by 20.

3 0
3 years ago
Here are the first five terms of a sequence.
Snezhnost [94]

Step-by-step explanation:

3 to 8= 5

8 to 17= 9

17 to 30= 13

30 to 47= 17

47 to 68= 21

68 to 93= 25

93 to 122= 29

122 to 155= 33

155 to 192= 37

difference is 4

solve by

2 {n}^{2}  - n + 2 \\ 2 {(9)}^{2}  - 9 + 2 \\ 2(81) - 9 + 2 \\ 162 - 9 + 2 \\ 153 + 2 = 155

5 0
3 years ago
T-5-2t+5 simplify expression
pav-90 [236]

Answer:

-t

Step-by-step explanation:

t - 5 - 2t + 5 =

t - 5 + 5 - 2t =

t - 2t =

-t

3 0
3 years ago
Read 2 more answers
Of the 100 entries in a costume contest, 39 entrants were dressed as heroes and 45 entrants were wearing a mask. If 21 entrants
ehidna [41]

Correct question with correct options has been attached

Answer:

37

Step-by-step explanation:

Let C represent those dressed as heroes and let B represent those wearing mask

Thus;

n(C) = 39

n(D) = 45

We are told that 21 entrants were dressed as heroes wearing a mask.

Thus; n(C n D) = 21

We are also told that there were a total of 100 entries.

Thus, n(T) = 100

Now, number of entrants neither dressed as heroes nor wearing a mask is given by;

n(T) - n(C u D)

n(C u D) = n(C) + n(D) - n(C n D)

n(C u D) = 39 + 45 - 21

n(C u D) = 63

Thus;number of entrants neither dressed as heroes nor wearing a mask is: 100 - 63 = 37

3 0
3 years ago
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