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1 year ago

What are the zeros of g(x)= x³ + 6x² - 9x-54?

Mathematics

1 answer:

Veseljchak [2.6K]1 year ago

3 0

Answer:

3,-3

Step-by-step explanation:

g(3)= (3)³+6(3)²-9(3)-54

= 27+54-27-54

=81-81

= 0

g(-3) = (-3)³+6(-3)²-9(-3)-54

= -27+54+27-54

= 27-27

= 0

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Answer:

______________________________________________________

TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-

For any right angled triangle with one angle α ,

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SOME GENERAL TRIGNOMETRIC FORMULAS :-

$\sin \alpha = \frac{1}{cosec \: \alpha }$ or $cosec \: \alpha = \frac{1}{\sin \alpha }$

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______________________________________________________

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

$\cos (90 - \alpha ) \times cosec(90 - \alpha )$

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$=> \sin\alpha \times \frac{1}{\cos\alpha }$

$=> \frac{\sin\alpha }{\cos\alpha }$

$=> \tan\alpha$ = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

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Answer:

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Step-by-step explanation:

I = prt

I = (2,400) (0.04) (2.5)

note: I changed 4% to a decimal and 30 months to 2.5 years

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I = 240 <-- The interest

------------------------------------------------------------------------------------------------------------

The simple interest accumulated on a principal of $ 2,400.00 at a rate of 4% per year for 2.5 years (30 months) is $240.00.

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* Last time I did interest was in 6th grade and I don't remember much. So I am very sorry if my answer is wrong *

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