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sveticcg [70]
3 years ago
8

Marie has a small copy of Renny Margaret's famous painting the Schoolmaster her copy has the dimensions of 2 inch by 1.5 in the

scale of the copy is the one in 40 cm find the dimensions of the original painting ​
Mathematics
1 answer:
Alexandra [31]3 years ago
6 0

Answer:

The answer is 743.4 square inches

Step-by-step explanation:

1. find the length-   2 x 40=80 cm

2. find the width-  1.5 x 40= 60cm

3. find area (Length x width)-  80 x 60= 4800 square cm

4. find length but in inches-   1in=2.54cm  length=80/2.54 = 31.5 inches

5. find width but in inches-  width= 60/2.54= 23.6 inches

6. Find area(length x width)-  31.5 x 23.6= 743.4 square inches

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Assoli18 [71]

Answer:

A = 22.5 m²

Step-by-step explanation:

longest side length

b = √((-7 + 4)² + (-1 - 8)²) = √90

other sides

a = √((-1 + 7)² + (2 + 1)²) = √45

height

h = √((√45)² - (½√90)²) = √22.5

Area of triangle

A = ½bh = ½√90√22.5 = 22.5 m²

a little math shows that this triangle is a tilted half of a square with sides √45

4 0
3 years ago
Please use the Quadratic Formula to find the zeros of the function below.<br> g(x) = 2x2 + x + 25
Ksivusya [100]

Answer:

Step-by-step explanation:

7 0
3 years ago
Which congruence theorem can be used to prove △BDA ≅ △DBC? Triangles B D A and D B C share side D B. Angles C B D and A D B are
Tomtit [17]

Answer:

A. Hypotenuse-leg (HL) congruence.

HL, when you have 2 right triangles and their hypotenuses are congruent you are able to say HL

Step-by-step explanation:

We know that the hypotenuse-leg theorem states that if the hypotenuse and one leg of a right triangle are congruent to hypotenuse and corresponding leg of another right triangle, then the triangles are congruent.  

hypotenuse(AB) of △BDA equals to hypotenuse (CD) of △DBC.  

BDA and DBC share a common side DB.

Using Pythagorean theorem we will get,

CD^{2}=DB^{2}+BC^{2}...(1)  \\\\AB^{2}=DB^{2}+AD^{2}...(2)

We have been given that CD=AB, Upon using this information we will get,

DB^{2}+BC^{2}=DB^{2}+AD^{2}

Upon subtracting DB^{2} from both sides of our equation we will get,

BC^{2}=AD^{2}\\\\BC=AD

<h3>Therefore, by HL congruence △BDA ≅ △DBC.</h3>
6 0
3 years ago
Read 2 more answers
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Marta_Voda [28]

Answer:

12.

Step-by-step explanation:

I'm sorry. I really don't know what you mean. I just wrote 12 because you want only the number twelve?

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3 years ago
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Lady_Fox [76]

Answer:

196 cm²

Step-by-step explanation:

[Area of Triangle BCD]

A = \frac{1}{2}bh = \frac{1}{2} * 28 * 6 = 84 cm²

[Area of Triangle ABD]

A = \frac{1}{2}bh = \frac{1}{2} * 28 * 8 = 112 cm²

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3 years ago
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