Isolate the variable by dividing each side by factors that don't contain the variable.
a=- \frac{ x^{2}- \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2} ,- \frac{ x^{2}+ \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2}
Solve for b by simplifying both sides of the equation then isolating the variable.
b= \frac{12}{x}+ \frac{72}{ x^{2} }-2+2a- \frac{4a}{x}+ \frac{ a^{2} }{x}- \frac{2a^{z} }{ x^{2} }
Hopefully i helped ^.^ Mark brainly if possible. Lol once again i saw the same question so why not answer it again!
Well if you think about it, you are given 2 equations. lets say the 2 numbers ar x and y
it says one number that we willl call y is 4 times another number we will call x. so:
y = 4 * x
the other part says their difference is 24. well y has to be the larger number sincenit is 4 times x. so:
y - x = 24
in the first part i said y = 4x so i know what y equals. i can plug this into thenother equation like this
y - x = 24
(4x) - x = 24
3x = 24
x = 8
i have x. i can plug this in first equation to find y
y = 4x
y = 4 (8)
y = 32
we can checj by plugging in x and y to both equations. if it matches we are.good
y = 4x
32 = 4 (8)
32 = 32
y - x = 24
(32) - (8) = 24
24 = 24
it all works out
2 3/4 hours is 165 minutes
1hr and 55 min is 115 minutes
So 2 3/4 hours is 50minutes longer than 1hr and 55 min.
