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xz_007 [3.2K]
3 years ago
12

Express as the sum or difference of logarithms. log311y

Mathematics
1 answer:
vovikov84 [41]3 years ago
8 0

Answer:

log311y=log311+logy

Step-by-step explanation:

We can use the property of logarithms of sum of logarithms:

log_{b} (M*N)=log_{b} M+log_{b}N

So, if we consider M=311 and N=y

We replace

log311y=log311+logy

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Generate the first 7 terms of the sequence defined by Q = 3n+ 5.​
d1i1m1o1n [39]

Answer:

8,11,14,17,20,23,26

Step-by-step explanation:

Q = 3n+ 5

an=3n+5

a1=3(1)+5=8

a2=3(2)+5=11

a(3)=3(3)+5=14

a4=3(4)+5=17

a5=3(5)+5=20

a6=23

a7=26

8 0
3 years ago
Which of the following equations is equivalent to 3(2p + 4) - (3p - 4) = 43?
emmainna [20.7K]
Answer: (use distributive property then add the like terms)
3(2p + 4) - (3p - 4) = 43
6p + 12 - 3p - 4 = 43
3p - 8 = 43
6 0
3 years ago
Essential: Solve the proportions<br> step by step ​
vazorg [7]

Answer:

The value of r=\frac{-106}{47}

The value of x=\frac{83}{32}

Step-by-step explanation:

Given that,

A) \frac{2r-2}{7r+10} = \frac{9}{8}

Now,

\frac{2r-2}{7r+10} = \frac{9}{8}

8(2r-2)=9(7r+10)

16r-16=63r+90

-16-90=63r-16r

-(16+90)=47r

-106=47r

r=\frac{-106}{47}

B) \frac{x+4}{9} = \frac{3(x-2)-1}{5}

Now,

\frac{x+4}{9} = \frac{3(x-2)-1}{5}

5(x+5)=9[3(x-2)-1]

5x+25=9[3x-6-1]

5x+25=9[3x-7]

5x+25=27x-63

25+63=27x+5x

83=32x

x=\frac{83}{32}

6 0
4 years ago
This is due in 10 minutes please help me
valkas [14]

Given:

The rate of interest on three accounts are 7%, 8%, 9%.

She has twice as much money invested at 8% as she does in 7%.

She has three times as much at 9% as she has at 7%.

Total interest for the year is $150.

To find:

Amount invested on each rate.

Solution:

Suppose x be the amount invested at 7%. Then,

The amount invested at 8% = 2x

The amount invested at 9% = 3x

Total interest for the year is $150.

x\times \dfrac{7}{100}+2x\times \dfrac{8}{100}+3x\times \dfrac{9}{100}=150

Multiplying both sides by 100, we get

7x+16x+27x=15000

50x=15000

Dividing both sides by 50, we get

x=\dfrac{15000}{50}

x=300

So, the amount invested at 7% is 300.

The amount invested at 8% is

2(300)=600

The amount invested at 9% is

3(300)=900

Hence, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.

7 0
3 years ago
Rachelle buys a drink. She spends the same amount of money on her drink as Chuck spent on his candy. Rachelle now has only 1/3 o
Bad White [126]

Answer:

$1.80

Step-by-step explanation:

2/3x = 1.2

x = 1.2 / (2/3)

x = 1.2 * (3/2)

x = 1.80

5 0
3 years ago
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