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xz_007 [3.2K]
3 years ago
12

Express as the sum or difference of logarithms. log311y

Mathematics
1 answer:
vovikov84 [41]3 years ago
8 0

Answer:

log311y=log311+logy

Step-by-step explanation:

We can use the property of logarithms of sum of logarithms:

log_{b} (M*N)=log_{b} M+log_{b}N

So, if we consider M=311 and N=y

We replace

log311y=log311+logy

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Answer:

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Step-by-step explanation:

Given that:

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I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix}  \dfrac{(\sqrt{81 -y^2})^2 }{2}-0  \end {bmatrix}     \ dxdy

I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix}  \dfrac{{81 -y^2} }{2} \end {bmatrix}     \ dxdy

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I = \dfrac{1}{18} \int^9_{y=0}  \begin {bmatrix}  {81 \  y -y^3}  \end {bmatrix}     \ dy

I = \dfrac{1}{18}  \begin {bmatrix}  {81 \ \dfrac{y^2}{2} - \dfrac{y^4}{4}}  \end {bmatrix}^9_0

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I = \dfrac{1}{18}  \begin {bmatrix}  3280.5 - 1640.25  \end {bmatrix}

I = \dfrac{1}{18}  \begin {bmatrix}  1640.25  \end {bmatrix}

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