Question

Express as the sum or difference of logarithms. log311y

Answer 1

Answer:

$log311y=log311+logy$

Step-by-step explanation:

We can use the property of logarithms of sum of logarithms:

$log_{b} (M*N)=log_{b} M+log_{b}N$

So, if we consider $M=311$ and $N=y$

We replace

$log311y=log311+logy$