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crimeas [40]
3 years ago
14

A veterinarian cares for cats and dogs. She cares for 91cats. If she cares for 7 cats for every 5 dogs how many dog does she car

e for?
Mathematics
1 answer:
77julia77 [94]3 years ago
5 0
If she cares for 7 cats for every 5 dogs then you would divide 91 by 7 then that would give you 13. then you would multiply 13 by 5 then that would give you 65. so therefore she has 65 dogs. 

91/7=13
13*5=65
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HELPPPP
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Dilation about the origin multiplies every coordinate by the scale factor.

C' = 4(-5, 2) = (-20, 8)

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7 0
3 years ago
Adrian's CD player can hold six disks at a time and shuffles all of the albums and their songs. If he has thirteen CD's, how man
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Adrian can put a total of 1716 combinations in the player. 

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total combinations = n!/[r! *(n-r)!]
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6 0
3 years ago
Dogs are inbred for such desirable characteristics as blue eye color, but an unfortunate by-product of such inbreeding can be th
sesenic [268]

Answer:

The probability that the dogs are blue eyed and deaf is 13.02%.

Step-by-step explanation:

We are given the following information in the question:

P(Blue eyes) = 31%

P(Deaf) = 38%

P(Deaf | Blue eyes) = 42%

Formula for conditional probability:

P( A|B) = \displaystyle\frac{P(A \cap B)}{P(B)}

Now, let A be the event where the dog is deaf and B be the the event where dog is blue eyed.

P( \text{ Deaf}|\text{Blue eyes}) = \displaystyle\frac{P( \text{Deaf} \cap \text{Blue eyes})}{P(\text{Blue eyes})}\\\\0.42 = \displaystyle\frac{P( \text{Deaf} \cap \text{Blue eyes})}{0.31}\\\\P( \text{Deaf} \cap \text{Blue eyes}) = 0.42\times 0.31 = 0.1302 = 13.02\%

Hence, the probability that the dogs are blue eyed and deaf is 13.02%.

6 0
2 years ago
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