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Vlad [161]
4 years ago
12

What are the solutions to the equation x- 7/x = 6 ?

Mathematics
2 answers:
OLEGan [10]4 years ago
7 0

Answer:none of these.

Try to substitute any of the given values for x and the result is false

Step-by-step explanation:

Try x=1. 1-7 -6. Divide that by 1 and you get -6 = 6. False!

To solve the given equation, multiply sides by x to cancel the denominator. You get x-7 = 6x then subtract x from both sides to get -7=5x. Divide both sides by 5 to get x= -7/5

But if the original equation has an x^2 somewhere, there will be a different set of solutions.

ahrayia [7]4 years ago
3 0

Answer:

x=-1 and  x=7

Step-by-step explanation:

C

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Given rs || qp, what is the value of x?
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In the given figure,

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I need help with this problem. Given: BC = 10 inches AC = √50 inches m∠CBD = 60° m∠CAD = 90° Calculate the exact area of the sha
Nikitich [7]

Answer:

Area of the shaded region = 23.33 in²

Step-by-step explanation:

Area of a sector = \frac{\theta}{360}(\pi r^{2})

Where θ = Central angle subtended by an arc

r = radius of the circle

Area of the sector BCD = \frac{60}{360}(\pi) (10^{2})

                                       = 52.36 in²

Area of equilateral triangle BCD = \frac{\sqrt{3} }{4}(\text{Side})^2

                                                      = \frac{\sqrt{3} }{4}(10)^2

                                                      = 25\sqrt{3} in²

                                                      = 43.30 in²

Area of the shaded portion in ΔBCD = 52.36 - 43.3

                                                             = 9.06 in²

Area of sector CAD = \frac{90}{360}(\pi)(\sqrt{50})^2

                                 = 39.27 in²

Area of right triangle CAD = \frac{1}{2}(\text{Base})(\text{Height})

                                            = \frac{1}{2}(\text{AC})(\text{AD})

                                            = \frac{1}{2}(\sqrt{50})(\sqrt{50})

                                            = 25 in²

Area of the shaded part in the ΔACD = 39.27 - 25

                                                                         = 14.27 in²

Area of the shaded part of the figure = 9.06 + 14.27

                                                                = 23.33 in²

8 0
3 years ago
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